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POhow to initialize generic functions in c
 

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    <p>Im trying a simple example of the usage of a generic comparison-function in c but when initializing it I get the warning message that the types are incompatible when initializing them. Feels as I am missing something basic here...</p> <pre><code>#include &lt;stdio.h&gt; #include &lt;string.h&gt; int compare(int (*comp)(void *first, void *second), void *arr, int size) { int i, j, dups=0, arrsize=sizeof(arr)/size; for(i=0; i&lt;arrsize; i++) { for(j=0; j&lt;arrsize; j++) { if(j!=i) dups+=(*comp)(&amp;arr[i], &amp;arr[j]); } } return dups; } int compareints(int *first, int *second) { if(*first==*second) return 1; return 0; } int main(int argc, const char * argv[]) { int (*comp)(void *, void *)=&amp;compareints; //Here is where I get the warning... int arr[10]={22, 39, 78, 22, 99, 12, 82, 10, 11, 28}; printf("The arr has dups: %d\n", compare(comp, arr, sizeof(int))); return 0; } </code></pre> <p>EDIT: the program was not functioning properly and it had to do with the handling of the array. The modifications for functioning prog are below:</p> <pre><code>int compare(int (*comp)(void *first, void *second), void **arr, int size) .... .... .... dups+=(*comp)(arr[i], arr[j]); int compareints(....) if((*((int *)first))==(*((int *)second))) return 1; int main(int argc, const char * argv[]) { int (*comp)(void *, void *)=&amp;compareints; int arr[10]={22, 39, 78, 22, 99, 12, 82, 10, 11, 28}; void **arr2=malloc(sizeof(int *)*10); for(int i=0; i&lt;10; i++) { arr2[i]=&amp;arr[i]; } printf("The arr has dups: %d\n", compare(comp, arr2, 10)); return 0; } </code></pre>
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