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PO
primarykey
Id
13608112
data
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0
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0
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0
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CreationDate
2012-11-28T15:04:35.950
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0
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2012-11-28T15:04:35.950
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0
OwnerUserId
157247
ParentId
13608032
PostTypeId
2
Score
2
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0
LastEditorDisplayName
text
Body
The problem is that the functions you're creating have a reference to the <code>i</code> variable, not a copy of its value, and so when they run they see <code>i</code> as it is at that point in time (past the end of the array, presumably). (More: <a href="http://blog.niftysnippets.org/2008/02/closures-are-not-complicated.html" rel="nofollow">Closures are not complicated</a>) I'd recommend a completely different approach (below), but first, let's look at how to make your existing approach work. To do what you were trying to do, with the <code>for</code> loop, you have to have the functions close over something that won't change. The usual way to do that is to use a factory function that creates the timeout functions such that they close over the argument to the factory. Or actually, you can pass in the array element's value rather than the index variable. <pre><code>for(var i in my_array) { if(my_array.hasOwnProperty(i)) { setTimeout(makeFunction(my_array[i])); } } function makeFunction(entry) { return function(){ do_something_with_data(entry); }; } </code></pre> But, I would probably restructure the code so you're not creating masses and masses of function objects unnecessarily. Instead, use one function, and have it close over an index that it increments: <pre><code>// Assumes `my_array` exists at this point, and that it // has at least one entry var i = 0; setTimeout(tick, 0); function tick() { // Process this entry if (my_array.hasOwnProperty(i)) { do_something_with_data(my_array[i]); } // Move to next ++i; // If there are any left, schedule the next tick if (i < my_array.length) { setTimeout(tick, 0); } } </code></pre>
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1. POCannot access array elements properly within setTimeout
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1. PTAnswer
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1. UST.J. Crowder
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2. VO
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