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POKinect skeleton Scaling strange behaviour
 

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  1. POKinect skeleton Scaling strange behaviour
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    <p>I am trying to scale a skeleton to match to the sizes of another skeleton. My algoritm do the following:</p> <ul> <li>Find the distance between two joints of the origin skeleton and the destiny skeleton using phytagorean teorem</li> <li>divide this two distances to find a multiply factor.</li> <li>Multiply each joint by this factor.</li> </ul> <p>Here is my actual code:</p> <pre><code>public static Skeleton ScaleToMatch(this Skeleton skToBeScaled, Skeleton skDestiny) { Joint newJoint = new Joint(); double distanciaOrigem = 0; double distanciaDestino = 0; double fator = 1; SkeletonPoint pos = new SkeletonPoint(); foreach (BoneOrientation bo in skToBeScaled.BoneOrientations) { distanciaOrigem = FisioKinectCalcs.Distance3DBetweenJoint(skToBeScaled.Joints[bo.StartJoint], skToBeScaled.Joints[bo.EndJoint]); distanciaDestino = FisioKinectCalcs.Distance3DBetweenJoint(skDestiny.Joints[bo.StartJoint], skDestiny.Joints[bo.EndJoint]); if (distanciaOrigem &gt; 0 &amp;&amp; distanciaDestino &gt; 0) { fator = (distanciaDestino / distanciaOrigem); newJoint = skToBeScaled.Joints[bo.EndJoint]; // escaling only the end joint as the BoneOrientatios starts from HipCenter, i am scaling from center to edges. // applying the new values to the joint pos = new SkeletonPoint() { X = (float)(newJoint.Position.X * fator), Y = (float)(newJoint.Position.Y * fator), Z = (float)(newJoint.Position.Z * fator) }; newJoint.Position = pos; skToBeScaled.Joints[bo.EndJoint] = newJoint; } } return skToBeScaled; } </code></pre> <p>Every seems to work fine except for the hands and foots</p> <p>Look at this images</p> <p><img src="https://i.stack.imgur.com/q9uMG.jpg" alt="enter image description here"> <img src="https://i.stack.imgur.com/nj0Pu.jpg" alt="enter image description here"></p> <p>I have my own skeleton over me, and my skeleton scaled to the sizes of another person, but the hands and foots still crazy. (but code looks right)</p> <p>Any suggestion? </p>
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