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PO
 

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  1. PO
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    <p>The greedy options is just for nested elements that have a droppable parent.</p> <p>In your code the 2 droppable elements are siblings so the greedy option will not work:</p> <pre><code>&lt;div id="droppable3" class="ui-widget-header"&gt; &lt;p&gt;Outer droppable&lt;/p&gt; &lt;/div&gt; &lt;div id="droppable3-inner" class="ui-widget-header"&gt; &lt;p&gt;Inner droppable (greedy)&lt;/p&gt; &lt;/div&gt; </code></pre> <p>Here is a messy workaround if you still want to use siblings instead of parents and children.</p> <p>Live code <a href="http://jsfiddle.net/nameIsNull/FgUYm/" rel="nofollow">example</a>.</p> <pre><code>function normalDraggedOver() { $( this ).addClass( "ui-state-highlight" ) .find( "&gt; p" ) .html( "Droppeeeed!" ); } var options = { activeClass: "ui-state-hover", hoverClass: "ui-state-active", greedy: true, drop: normalDraggedOver }; var options2 = { activeClass: "ui-state-hover", hoverClass: "ui-state-active", disabledClass: "ui-state-disabled", hoverStateClass: "ui-state-hover", greedy: true, greedyWithSibligs: true, drop: normalDraggedOver, over: function () { /* if we have previous siblings of the inner element we handle them as parents */ if(options2.greedyWithSibligs &amp;&amp; $(this).prev().length &gt; 0) { $(this).siblings().slice(0, $(this).index()) .removeClass(options2.hoverClass) .droppable('disable') .removeClass(options2.disabledClass) .removeClass(options2.hoverStateClass); } }, out: function () { /* all the siblings of the inner element that were handled as parents act as one*/ if(options2.greedyWithSibligs &amp;&amp; $(this).prev().length &gt; 0) { $(this).siblings().slice(0, $(this).index()) .droppable('enable') .addClass(options2.hoverClass); console.log($(this).attr('id')); } } }; </code></pre>
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    1. POCreating multiple droppable siblings that at positioned on top of eachother
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    1. USAlexandruSerban
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    1. COWell, I’m still looking for an even more general solution: the droppables should not have to be siblings. I just want absolutely-positioned droppables to respect the `z-index` so when dropping onto an element that visually lies in front of another (that is also droppable), the drop should only register on the front element.
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      1. USRaphael Schweikert
    2. COThe problem with z-index is that it will always have the value 'auto' if you didn't set it yourself.
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      1. USAlexandruSerban
 

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