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POHow to add values accordingly of the first indices of a dictionary of tuples of a list of strings? Python 3x
 

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  1. POHow to add values accordingly of the first indices of a dictionary of tuples of a list of strings? Python 3x
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    <p>I'm stuck on how to formulate this problem properly and the following is:</p> <p>What if we had the following values:</p> <pre><code>{('A','B','C','D'):3, ('A','C','B','D'):2, ('B','D','C','A'):4, ('D','C','B','A'):3, ('C','B','A','D'):1, ('C','D','A','B'):1} </code></pre> <p>When we sum up the first place values: [5,4,2,3] (5 people picked for A first, 4 people picked for B first, and so on like A = 5, B = 4, C = 2, D = 3)</p> <p>The maximum values for any alphabet is 5, which isn't a majority (5/14 is less than half), where 14 is the sum of total values.</p> <p>So we remove the alphabet with the fewest first place picks. Which in this case is C.</p> <p>I want to return a dictionary where <code>{'A':5, 'B':4, 'C':2, 'D':3}</code> <strong>without importing</strong> anything.</p> <p>This is my work: </p> <pre><code>def popular(letter): '''(dict of {tuple of (str, str, str, str): int}) -&gt; dict of {str:int} ''' my_dictionary = {} counter = 0 for (alphabet, picks) in letter.items(): if (alphabet[0]): my_dictionary[alphabet[0]] = picks else: my_dictionary[alphabet[0]] = counter return my_dictionary </code></pre> <p>This returns duplicate of keys which I cannot get rid of.</p> <p>Thanks.</p>
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    1. USAndrew Clark
    1. USTheStruggler
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    1. COOne of your classmates is working on [the same homework problem](http://stackoverflow.com/questions/13569105/how-to-properly-eliminate-elements-in-dictionary-until-one-string-remains/13569432).
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      1. POHow to add values accordingly of the first indices of a dictionary of tuples of a list of strings? Python 3x
      1. USPeterBB
 

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