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POHow to properly eliminate elements in dictionary until one string remains
 

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  1. POHow to properly eliminate elements in dictionary until one string remains
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    <p>I really need help on this</p> <pre><code>def get_winner (dict_winner): new_dict = {} for winner in dict_winner: first_letter = winner[0] value = dict_winner[winner] if first_letter in new_dict: new_dict[first_letter] += value else: new_dict[first_letter] = value return (new_dict) get_winner({ ('C', 'A', 'B', 'D') :3, ('D', 'B', 'C', 'A') :2, ('C', 'D', 'A', 'B') :1, ('A', 'D', 'B', 'C') :2, ('A', 'D', 'C', 'B') :4, ('A', 'C', 'D', 'B') :2 }) #Outputs {'A': 8, 'D': 2, 'C': 4} </code></pre> <p>Now I want the result be a tuple of str, NoneType..</p> <p>Also, it is eliminating only the letter with the smallest value in first place only one time. I want it to repeat this process until I get one winner in the end. So in this case all the B's will be eliminated in the dict itself, not in the output. for example:</p> <pre><code>first time = [8, 0, 4, 2] second time = { ('C', 'A', 'D') :3, ('D', 'C', 'A') :2, ('C', 'D', 'A') :1, ('A', 'D', 'C') :2, ('A', 'D', 'C') :4, ('A', 'C', 'D') :2 }) #Outputs C = 4 D = 2 A = 8 third time= { ('C', 'A') :3, ('C', 'A') :2, ('C', 'A') :1, ('A', 'C') :2, ('A', 'C') :4, ('A', 'C') :2 }) #Outputs C = 6 A = 8 </code></pre> <p>8/ 14 > 50%, I know that should have been the case since the beginning because <code>A</code> already had the majority value. But i am assuming <code>A</code> has a value of 40% which is when elimination should begin. So, could you point out where I went wrong in coding this? In the example <code>A</code> should be the winner! So the output shopuld be ('A', None)</p>
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    1. COAre you attempting to implement [Condorcet voting](http://en.wikipedia.org/wiki/Condorcet_method)?
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      1. USDan D.
    2. COYour dicts contains duplicate keys?? `third_time` will be actually passed as `{('A', 'C'): 2, ('C', 'A'): 1}`
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      1. USAshwini Chaudhary
 

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