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    <p>Here's another approach, based on dmckee's work, demonstrating just how readable Python is:</p> <h1>Python</h1> <p>244 characters</p> <pre><code>def h(l):p=2*ord(l.upper())-88;a,n=map(ord,"AF__GF__]E\\E[EZEYEXEWEVEUETE__________CF__IBPDJDPBGAHDPC[DNBSDJCKDOBJBTCND`DKCQCHAHCZDSCLD??OD"[p:p+2]);return "--..--..-.-.-..--...----.....-----.-"[a-64:a+n-128] def e(s):return ' '.join(map(h,s)) </code></pre> <p>Limitations:</p> <ul> <li>dmckee's string missed the 'Y' character, and I was too lazy to add it. I think you'd just have to change the "??" part, and add a "-" at the end of the second string literal</li> <li>it doesn't put '/' between words; again, lazy</li> </ul> <p>Since the rules called for fewest <em>characters</em>, not fewest <em>bytes</em>, you could make at least one of my lookup tables smaller (by half) if you were willing to go outside the printable ASCII characters.</p> <p>EDIT: If I use naïvely-chosen Unicode chars but just keep them in escaped ASCII in the source file, it still gets a tad shorter because the decoder is simpler:</p> <h1>Python</h1> <p>240 characters</p> <pre><code>def h(l):a,n=divmod(ord(u'\x06_7_\xd0\xc9\xc2\xbb\xb4\xad\xa6\x9f\x98\x91_____\x14_AtJr2&lt;s\xc1d\x89IQdH\x8ff\xe4Pz9;\xba\x88X_f'[ord(l.upper())-44]),7);return "--..--..-.-.-..--...----.....-----.-"[a:a+n] def e(s):return ' '.join(map(h,s)) </code></pre> <p>I think it also makes the intent of the program much clearer.</p> <p>If you saved this as UTF-8, I believe the program would be down to 185 characters, making it the shortest complete Python solution, and second only to Perl. :-)</p>
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    1. POConvert a string into Morse code
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    1. COI've fixed my table to support both the Y *and* the word bounday by encoding spaces.
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