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    <p>That's fun. The function separates buffer to an array of strings, where it hits a white-space delimiter.</p> <pre><code>void parse_args(char *buffer, char** args, size_t args_size, size_t *nargs) { char *buf_args[args_size]; /* You need C99 */ char **cp; char *wbuf; size_t i, j; </code></pre> <p>Initialization code...</p> <pre><code> wbuf=buffer; buf_args[0]=buffer; args[0] =buffer; </code></pre> <p>Set all pointers to the beginning of the buffer</p> <pre><code> for(cp=buf_args; (*cp=strsep(&amp;wbuf, " \n\t")) != NULL ;){ </code></pre> <ol> <li>Set the write pointer <code>cp</code> to point to the first element in the buf_args array.</li> <li><p>Set *cp to the next instance of a non-whitespace token in the buffer, and advance <code>wbuf</code> to its ending position</p> <pre><code> if ((*cp != '\0') &amp;&amp; (++cp &gt;= &amp;buf_args[args_size])) break; </code></pre></li> </ol> <p>Stop when <code>strsep</code> returned NULL, or when it points to the end of the buffer, or when it points beyond the end of buf_args[]</p> <pre><code> } for (j=i=0; buf_args[i]!=NULL; i++){ if(strlen(buf_args[i])&gt;0) args[j++]=buf_args[i]; } </code></pre> <p>This loop creates a condensed copy of the buf_args[] array: it copies only the arguments which aren't empty strings. I guess that could happen if your source buffer had a series of consecutive white-space characters. </p> <pre><code> *nargs=j; args[j]=NULL; } </code></pre> <p>Put a NULL at the end of the output array and set the <code>nargs</code> output argument.</p>
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    1. COcould you explain exactly what strsep , strlen for example i insert this command ls -al how these two function will work
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