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POHaskell create a list with specific increment
 

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  1. POHaskell create a list with specific increment
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    <p>In the mathematical languages, you can create a vector as follows:</p> <pre><code>x = seq(0, 2*pi, length.out = 100) </code></pre> <p>This outputs:</p> <pre><code>[1] 0.00000000 0.06346652 0.12693304 0.19039955 0.25386607 0.31733259 0.38079911 [8] 0.44426563 0.50773215 0.57119866 0.63466518 0.69813170 0.76159822 0.82506474 [15] 0.88853126 0.95199777 1.01546429 1.07893081 1.14239733 1.20586385 1.26933037 [22] 1.33279688 1.39626340 1.45972992 1.52319644 1.58666296 1.65012947 1.71359599 [29] 1.77706251 1.84052903 1.90399555 1.96746207 2.03092858 2.09439510 2.15786162 [36] 2.22132814 2.28479466 2.34826118 2.41172769 2.47519421 2.53866073 2.60212725 [43] 2.66559377 2.72906028 2.79252680 2.85599332 2.91945984 2.98292636 3.04639288 [50] 3.10985939 3.17332591 3.23679243 3.30025895 3.36372547 3.42719199 3.49065850 [57] 3.55412502 3.61759154 3.68105806 3.74452458 3.80799110 3.87145761 3.93492413 [64] 3.99839065 4.06185717 4.12532369 4.18879020 4.25225672 4.31572324 4.37918976 [71] 4.44265628 4.50612280 4.56958931 4.63305583 4.69652235 4.75998887 4.82345539 [78] 4.88692191 4.95038842 5.01385494 5.07732146 5.14078798 5.20425450 5.26772102 [85] 5.33118753 5.39465405 5.45812057 5.52158709 5.58505361 5.64852012 5.71198664 [92] 5.77545316 5.83891968 5.90238620 5.96585272 6.02931923 6.09278575 6.15625227 [99] 6.21971879 6.28318531 </code></pre> <p>How can this be achieved in Haskell?</p> <p>I tried creating a lambda function and using it with map, but I could n't get the same output.</p> <p>Thanks</p> <pre><code>let myPi = (\x -&gt; 2*pi) map myPi [1..10] </code></pre>
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    1. USuser557240
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      1. VTUpMod
    1. COAlso in Haskell it need not be finite.
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      1. USJakub Hampl
    2. COYour lambda doesn't seem to use the `x` at all?
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      1. USsingpolyma
 

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