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POInterlocking Two Strings in Python ProblemSetQuestion (Self-Taught)
 

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    <p>Winkleson here! I am currently learning Python when I got stuck on a problem. I've gotten to the point where I'm dizzy just thinking about it :P Anyways any help would be greatly appreciated! Thanks in advance!</p> <p>Question:</p> <hr> <blockquote> <p><strong>Interlock</strong> </p> <p>Create a function that takes two strings that are the same length or within one character of the same length as parameters. It should then take these two strings and interlock them, taking one character from each string, interlocking them. If the strings are different lengths, then the result should always start with the longer string.</p> </blockquote> <p>My Coding (sorry I'm a beginner and it's not very Pythonic :P):</p> <hr> <pre><code>def interlock(s1, s2): r = 0 l1 = [] l2 = [] inters = '' for i in range(len(s1)): l1.append(i) for i in range(len(s2)): l2.append(i) if len(s2) == len(s1): for i in range(len(s1)): inters += ''.join(s1[i]) inters += ''.join(s2[i]) elif len(s1) &lt; len(s2): for i in range(len(s1)): inters += ''.join(s2[i]) inters += ''.join(s1[i]) r = i inters += ''.join(s2[r]) elif len(s2) &lt; len(s1): for i in range(len(s2)): inters += ''.join(s1[i]) inters += ''.join(s2[i]) r = i inters += ''.join(s1[r]) else: pass return inters </code></pre> <p>Results (what results I recieve):</p> <pre><code>___________________________________________________________________________________________ Call Expected Received Correct interlock('shoe','cold') schooled schooled true interlock('flat','etry') feltarty feltarty true **interlock('ab','siy') saiby saibi false** **interlock('abalone','hammer') ahbaamlmoenre ahbaamlmoenrn false** interlock('','a') a a true ___________________________________________________________________________________________ </code></pre> <p>The two bolder fields are where I am having the most issues. If I try to add in the last characters I get a mysterious out of range exception. Any ideas/solutions would be greatly appreciated! - Winkleson</p> <p>P.s This is shorter than my normal posts... Usually I'll give an (un)accurate idea on what I'm think I'm doing wrong and it drags on and on and on and on.... you get the idea. Anyways I probably broke my loops like an idiot. So... Goodluck!</p> <p><strong>THANKS</strong></p> <p>Thank you everyone who suggested ways to become a better programmer! I don't get much time in a day to program so it's great when so many people take time out of their day to suggest stuff. I love this website and it's community :)</p>
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    1. CO@Marcin Thanks for the edit :P
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    2. COA few comments. `join` is unnecessary here. You could just do `inters += s1[i]`, etc. Also, to break a string into a list is as easy as `list(s1)`
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    3. COI really want to answer `''.join(itertools.chain(*zip(s1, s2)))`, but that doesn't meet your requirements. :( What a shame.
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