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POends_with function: One string at the end of the other and Vise Versa in Python. Issue with solution assist?
 

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  1. POends_with function: One string at the end of the other and Vise Versa in Python. Issue with solution assist?
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    <p>Not the greatest title ever... Anyways Hello! I am currently answering this question but I am not meeting all the exceptions D: Any help would be amazing! (Sorry again for the crappy title).</p> <p>Question:</p> <hr> <p>Ends With Given two strings, return True if either of the strings appears at the very end of the other string, ignoring upper/lower case differences (in other words, the computation should not be "case sensitive").</p> <p>Examples / Tests:</p> <hr> <pre><code>&gt;&gt;&gt; end_other('Hiabc', 'abc') True &gt;&gt;&gt; end_other('AbC', 'HiaBc') True &gt;&gt;&gt; end_other('abc', 'abXabc') True </code></pre> <p>Test Results:</p> <hr> <pre><code>Call Expected Received Correct end_other('Hiabc', 'abc') True True true end_other('AbC', 'HiaBc') True True true end_other('abc', 'abXabc') True False false #Cond. Not being met end_other('Hiabcx', 'bc') False False true end_other('abc', 'abc') True True true end_other('xyz', '12xyz') True True true end_other('yz', '12xz') False False true end_other('ab', 'ab12') False False true </code></pre> <p>(Sorry for failed Formatting)</p> <p>My Code:</p> <hr> <pre><code>def end_other(s1,s2): s1 = s1.upper() s2 = s2.upper() if s1[2:6] == s2: return True elif s2[2:6] == s1: return True elif s2 == s1: return True else: return False </code></pre> <p>What I expect is wrong:</p> <hr> <p>The website I am using is not really known for it's solid answers... but I know it's quite possible there is a flaw in my code. So If you have any suggestions please let me know!</p>
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