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  1. POHow are integers internally represented at a bit level in Java?
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    <p>I am trying to understand how Java stores integer internally. I know all java primitive integers are signed, (except short?). That means one less bit available in a byte for the number.</p> <p>My question is, are all integers (positive and negative) stored as two's complement or are only negative numbers in two's complement?</p> <p>I see that the specs says <code>x bit two's complement number</code>. But I often get confused.</p> <p>For instance:</p> <pre><code> int x = 15; // Stored as binary as is? 00000000 00000000 00000000 00001111? int y = -22; // Stored as two complemented value? 11111111 11111111 11111111 11101010 </code></pre> <p><strong>Edit</strong></p> <p>To be clear, <code>x = 15</code> </p> <pre><code> In binary as is: `00000000 00000000 00000000 00001111' Two's complement: `11111111 11111111 11111111 11110001` </code></pre> <p>So if your answer is <code>all</code> numbers are stored as two's complement then:</p> <pre><code> int x = 15; // 11111111 11111111 11111111 11110001 int y = -22 // 11111111 11111111 11111111 11101010 </code></pre> <p>The confusion here again is the sign says, both are negative numbers. May be I am misreading / misunderstanding it?</p> <p><strong>Edit</strong> Not sure my question is confusing. Forced to isolate the question:</p> <p><strong>My question precisely: Are positive numbers stored in <code>binary as is</code> while negative numbers are stored as <code>two's complement</code>?</strong></p> <p>Some said all are stored in two's complement and one answer says only negative numbers are stored as two's complement.</p>
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