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    <p>This answer assumes you wish to validate a decimal "number" which meets the following criteria:</p> <h2>Definition of a "Number"</h2> <ul> <li>There must be at least one digit and all digits must be decimal (from 0 to 9).</li> <li>Both the integer and fractional parts are optional, but one or the other must be present.</li> <li>The fractional part, if present, may have any number of digits but is always preceded by a decimal point.</li> <li>If the integer part has more than one digit, the leading digit must not be zero.</li> <li>If the integer part has more than three digits, commas may be used to separate the integer into digit triplets.</li> <li>The number may begin with an optional sign, either a plus <code>+</code>, or a minus <code>-</code>.</li> <li>Whitespace is not allowed.</li> <li>An exponent part is not allowed.</li> </ul> <p>Given the above requirements here are some valid and invalid numbers</p> <h2>Valid "Numbers":</h2> <pre><code>0 0. .0 0.0 1 +1 -1 1234 123456 1,234 12,345 123,456 123,456.7890 </code></pre> <h2>Invalid "Numbers":</h2> <pre><code>0FA92 // Invalid digit. Must be 0-9. 0123 // Multi-digit integer must lead with non-zero. . // Must have at least one digit. 1,23,4 // Commas must separate triplets of digits. 12345,678. // Missing comma. + 10 // Whitespace not allowed. 1.2E34 // Exponents not allowed. </code></pre> <p>Here is a regex (first presented in commented, free-spacing mode format using Python's handy raw string syntax) which matches a number meeting the above requirements:</p> <h2>Regex to validate a "number"</h2> <pre class="lang-py prettyprint-override"><code>r""" ^ # Anchor to start of string. [+\-]? # Optional sign. (?=\.?\d) # Must have at least one digit. (?: # Optional integer part. Either... [1-9] # A sequence of digits w/no commas. \d* # (but first digit is not zero.) | # or an integer having commas... [1-9] # First digit is not zero. \d{0,2} # 1,2 or 3 digits ahead of 1st comma. (?: # One or more comma + 3 digits. , # Comma separates \d{3} # digit triplets. )+ # One or more comma + 3 digits. | 0 # or integer part may be just zero. )? # Optional integer part. (?: # Optional fractional part. \. # Dot separates \d* # zero or more fraction digits. )? # Optional fractional part. $ # Anchor to end of string. """ </code></pre> <p>Here is a JavaScript function which implements the above regex:</p> <h2>function isValidNumber()</h2> <pre class="lang-js prettyprint-override"><code>function isValidNumber(text) { var re = /^[+\-]?(?=\.?\d)(?:[1-9]\d*|[1-9]\d{0,2}(?:,\d{3})+|0)?(?:\.\d*)?$/; if((re.test(text))) return 'true'; return 'false'; } </code></pre> <p>Note that you should not be trying to validate the number until after the user has finished entering the entire number. Calling a validation function for each and every keypress (as your code above appears to be doing) is not good practice IMHO.</p>
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