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POHow can I adapt my regex to allow for escaped quotes?
 

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  1. POHow can I adapt my regex to allow for escaped quotes?
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    <h2>Introduction</h2> <p>First my general issue is that I want to string replace question marks in a string, but only when they are <em>not</em> quoted. So I found a similar answer on SO (<a href="https://stackoverflow.com/a/10929115/461813">link</a>) and began testing out the code. Unfortunately, of course, the code does not take into account escaped quotes.</p> <p>For example: <code>$string = 'hello="is it me your are looking for\\"?" AND test=?';</code></p> <p>I have adapted a regular expression and code from <a href="https://stackoverflow.com/a/10929115/461813">that answer</a> to the question: <a href="https://stackoverflow.com/questions/10928935/how-to-replace-words-outside-double-and-single-quotes/10929115">How to replace words outside double and single quotes</a>, which is reproduced here for ease of reading my question:</p> <pre><code>&lt;?php function str_replace_outside_quotes($replace,$with,$string){ $result = ""; $outside = preg_split('/("[^"]*"|\'[^\']*\')/',$string,-1,PREG_SPLIT_DELIM_CAPTURE); while ($outside) $result .= str_replace($replace,$with,array_shift($outside)).array_shift($outside); return $result; } ?&gt; </code></pre> <h2>Actual issue</h2> <p>So I have attempted to adjust the pattern to allow for it to match anything that is not a quote <code>"</code> and quotes that are escaped <code>\"</code>:</p> <pre><code>&lt;?php $pattern = '/("(\\"|[^"])*"' . '|' . "'[^']*')/"; // when parsed/echoed by PHP the pattern evaluates to // /("(\"|[^"])*"|'[^']*')/ ?&gt; </code></pre> <p>But this does not work as I had hoped.</p> <p>My test string is: <code>hello="is it me your are looking for\"?" AND test=?</code></p> <p>And I am getting the following matches:</p> <pre><code>array 0 =&gt; string 'hello=' (length=6) 1 =&gt; string '"is it me your are looking for\"?"' (length=34) 2 =&gt; string '?' (length=1) 3 =&gt; string ' AND test=?' (length=11) </code></pre> <p>Match index two should not be there. That question mark should be considered part of match index 1 only and not repeated separately.</p> <p>Once resolved this same fix should also correct the other side of the main alternation for single quotes/apostrophes as well <code>'</code>.</p> <p>After this is parsed by the complete function it should output:</p> <pre><code>echo str_replace_outside_quotes('?', '%s', 'hello="is it me your are looking for\\"?" AND test=?'); // hello="is it me your are looking for\"?" AND test=%s </code></pre> <p>I hope that this makes sense and I have provided enough information to answer the question. If not I will happily provide whatever you need.</p> <h2>Debug code</h2> <p>My current (complete) code sample is <a href="http://codepad.org/6dpepn2r" rel="nofollow noreferrer">on codepad for forking as well</a>:</p> <pre><code>function str_replace_outside_quotes($replace, $with, $string){ $result = ''; var_dump($string); $pattern = '/("(\\"|[^"])*"' . '|' . "'[^']*')/"; var_dump($pattern); $outside = preg_split($pattern, $string, -1, PREG_SPLIT_DELIM_CAPTURE); var_dump($outside); while ($outside) { $result .= str_replace($replace, $with, array_shift($outside)) . array_shift($outside); } return $result; } echo str_replace_outside_quotes('?', '%s', 'hello="is it me your are looking for\\"?" AND test=?'); </code></pre> <h2>Sample input and expected output</h2> <pre><code>In: hello="is it me your are looking for\\"?" AND test=? AND hello='is it me your are looking for\\'?' AND test=? hello="is it me your are looking for\\"?" AND test=?' AND hello='is it me your are looking for\\'?' AND test=? Out: hello="is it me your are looking for\\"?" AND test=%s AND hello='is it me your are looking for\\'?' AND test=%s hello="is it me your are looking for\\"?" AND test=%s AND hello='is it me your are looking for\\'?' AND test=%s In: my_var = ? AND var_test = "phoned?" AND story = 'he said \'where is it?!?\'' Out: my_var = %s AND var_test = "phoned?" AND story = 'he said \'where is it?!?\'' </code></pre>
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    1. COwhy does this *have* to be done with regular expressions? why not just create a simple loop: `for($i=0;$i<strlen($str);$i++) { if($str[$i]=='"') { /* skip to next '"' */ } else if($str[$i]=='?') { /* replace with something else */ } }` (but obviously adding a look-ahead for escaped quotes)
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      1. POHow can I adapt my regex to allow for escaped quotes?
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    2. COShort answer. It doesn't. Its just gotta work :)
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    3. COI think you should write a simple parser: read char by char and adjust accordingly.
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      1. USLuca Rainone
 

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