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POpython testing a decorated decorator through a mock
 

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    <p> This question is a follow-up to <a href="https://stackoverflow.com/a/1594484/1504046">this brilliant answer</a> on decorators in Python : </p> <p>I use the given "snippet to make any decorator accept generically any argument". </p> <p>Then I have this (here simplified) decorator:</p> <pre class="lang-py prettyprint-override"><code>@decorator_with_args def has_permission_from_kwarg(func, *args, **kwargs): """Decorator to check simple access/view rights by the kwarg.""" def wrapper(*args_1, **kwargs_1): if 'kwarg' in kwargs_1: kwarg = kwargs_1['kwarg'] else: raise HTTP403Error() return func(*args_1, **kwargs_1) return wrapper </code></pre> <ol> <li>Working with this decorator, no problem it does the job very well.</li> <li>Testing a similar decorator that does not require absolutely the kwargs, same outcome.</li> <li><p>But testing this decorator with the following mock does not work:</p> <pre class="lang-py prettyprint-override"><code>def test_can_access_kwarg(self): """Test simple permission decorator.""" func = Mock(return_value='OK') decorated_func = has_permission_from_slug()(func(kwarg=self.kwarg)) # It will raise at the following line, whereas the kwarg is provided... response = decorated_func() self.assertTrue(func.called) self.assertEqual(response, 'OK') </code></pre></li> </ol> <p>It returns me the exception I am raising when I do not have a 'kwarg' keyword-argument...</p> <p>Does anyone has a clue how to test (by mocking would be preferable) such a decorator decorated by another decorator that requires the access to one of the keyword arguments passed to the function ?</p>
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