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    <p>I think you misunderstood what the <code>java.io.File</code> class really represents. It is just a representation of the file on your system, i.e. its name, its path etc.</p> <p>Did you even look at the Javadoc for the <code>java.io.File</code> class? Have a look <a href="http://docs.oracle.com/javase/7/docs/api/java/io/File.html" rel="noreferrer">here</a> If you check the fields it has or the methods or constructor arguments, you immediately get the hint that all it is, is a representation of the URL/path.</p> <p>Oracle provides quite an extensive tutorial in their <a href="http://docs.oracle.com/javase/tutorial/essential/io/file.html" rel="noreferrer">Java File I/O tutorial</a>, with the latest NIO.2 functionality too.</p> <p>With NIO.2 you can read it in one line using <a href="http://docs.oracle.com/javase/7/docs/api/java/nio/file/Files.html#readAllBytes%28java.nio.file.Path%29" rel="noreferrer">java.nio.file.Files.readAllBytes()</a>.</p> <p>Similarly you can use <a href="http://docs.oracle.com/javase/7/docs/api/java/nio/file/Files.html#write%28java.nio.file.Path,%20byte%5B%5D,%20java.nio.file.OpenOption...%29" rel="noreferrer">java.nio.file.Files.write()</a> to write all bytes in your byte array.</p> <p><strong>UPDATE</strong></p> <p>Since the question is tagged Android, the more conventional way is to wrap the <code>FileInputStream</code> in a <code>BufferedInputStream</code> and then wrap that in a <code>ByteArrayInputStream</code>. That will allow you to read the contents in a <code>byte[]</code>. Similarly the counterparts to them exist for the <code>OutputStream</code>.</p>
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    1. POConvert file to byte array and vice versa
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    1. POConvert file to byte array and vice versa
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    1. COThis would be useful info if the question wasn't tagged Android. The `java.nio.file` package is not part of the Android SDK (which is based on Java 6).
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    2. COYou're right, I didn't notice it was tagged Android, I read the title and the question only. I will add the Java 6 way.
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