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POWhy does the compiler say pow(n,k) ambiguous in this code?
 

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  1. POWhy does the compiler say pow(n,k) ambiguous in this code?
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    <p>When compiling the following code under Xcode 4.5 (Mac), compilation fails with the following error message:</p> <pre><code>call to 'pow' is ambiguous </code></pre> <p>Why? Thanks!</p> <pre><code>#include &lt;iostream&gt; #include &lt;cmath&gt; #include &lt;limits&gt; using namespace std; int main() { cout &lt;&lt; "\tSquare root calculator using an emulation the ENIAC's algorithm." &lt;&lt; endl &lt;&lt; endl; long long m; while ((cout &lt;&lt; "Enter a positive integer:" &lt;&lt; endl) &amp;&amp; (!(cin &gt;&gt; m) || m &lt; 0 || m &gt; 9999999999)) //10-digit maxium { cout &lt;&lt; "Out of range."; cin.clear(); cin.ignore(std::numeric_limits&lt;std::streamsize&gt;::max(), '\n'); } again: long long l = m; //Find out how big the integer is and adjust k accordingly. int order = -1; long long temp = m; do { temp /= 10; order++; } while (temp/10); int k = order/2; //Step 1 long long a = -1; do { a+=2; m -= a*pow(100,k); } while (m &gt;= 0); while (k &gt; 0) { k--; //Step 2 if (m &lt; 0) { a = 10*a+9; for (;m &lt; 0;a -= 2) { m += a*pow(100,k); } a += 2; } //Step 3 else { a = 10*a-9; for(;m &gt;= 0;a += 2) { m -= a*pow(100,k); } a -= 2; } } //Step 4 cout &lt;&lt; endl &lt;&lt; "The square root of " &lt;&lt; l &lt;&lt; " is greater than or equal to " &lt;&lt; (a-1)/2 &lt;&lt; " and less than " &lt;&lt; (a+1)/2 &lt;&lt; "." &lt;&lt; endl &lt;&lt; endl; while ((cout &lt;&lt; "Enter a positive integer to calculate again, or zero to exit." &lt;&lt; endl) &amp;&amp; (!(cin &gt;&gt; m) || m &lt; 0 || m &gt; 9999999999)) { cout &lt;&lt; "Out of range."; cin.clear(); cin.ignore(std::numeric_limits&lt;std::streamsize&gt;::max(), '\n'); } if (m &gt; 0) goto again; return 0; } </code></pre>
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    1. PO
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    1. USWhozCraig
    1. USEamon Moloney
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    1. VO
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      1. POWhy does the compiler say pow(n,k) ambiguous in this code?
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      1. VTUpMod
    2. VO
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      1. POWhy does the compiler say pow(n,k) ambiguous in this code?
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      1. VTDownMod
    1. COThere's no `pow(int, int)` overload. Make one of the arguments a floating-point.
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      1. POWhy does the compiler say pow(n,k) ambiguous in this code?
      1. USchris
    2. COAs a side note, 9999999999 cannot fit into a long on 32-bit systems. Consider writing it 9999999999LL.
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      1. POWhy does the compiler say pow(n,k) ambiguous in this code?
      1. USBill
 

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