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13287201
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2012-11-08T10:30:23.147
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2012-11-08T10:49:03.197
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2012-11-08T10:49:03.197
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I think that agf's solution is pretty awesome -- lots of kudos to him. But I needed a couple more features: <ul> <li>to be able to have multiple links for one admin</li> <li>to be able to link to model in different app</li> </ul> Solution: <pre><code>def add_link_field(target_model = None, field = '', app='', field_name='link', link_text=unicode): def add_link(cls): reverse_name = target_model or cls.model.__name__.lower() def link(self, instance): app_name = app or instance._meta.app_label reverse_path = "admin:%s_%s_change" % (app_name, reverse_name) link_obj = getattr(instance, field, None) or instance url = reverse(reverse_path, args = (link_obj.id,)) return mark_safe("<a href='%s'>%s</a>" % (url, link_text(link_obj))) link.allow_tags = True link.short_description = reverse_name + ' link' setattr(cls, field_name, link) cls.readonly_fields = list(getattr(cls, 'readonly_fields', [])) + \ [field_name] return cls return add_link </code></pre> Usage: <pre><code># 'apple' is name of model to link to # 'fruit_food' is field name in `instance`, so instance.fruit_food = Apple() # 'link2' will be name of this field @add_link_field('apple','fruit_food',field_name='link2') # 'cheese' is name of model to link to # 'milk_food' is field name in `instance`, so instance.milk_food = Cheese() # 'milk' is the name of the app where Cheese lives @add_link_field('cheese','milk_food', 'milk') class FoodAdmin(admin.ModelAdmin): list_display = ("id", "...", 'link', 'link2') </code></pre> I am sorry that the example is so illogical, but I didn't want to use my data.
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1. POHow do I add a link from the Django admin page of one object to the admin page of a related object?
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1. USSummerBreeze
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1. COGreat improvements! Glad people are using / improving this.
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