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POHow To Get Variables Submitted by AJAX Using PHP Correctly?
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2012-11-08T05:11:39.027
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<p>I have this ajax/jquery code :</p> <pre><code>var headline = $("input#headline").val(); var subheadline = $("textarea#subheadline").val(); var pics = $("input#pics").val(); var dataString = 'headline='+ headline + '&subheadline=' + subheadline + '&pics=' + pics; $(".save-notice").hide(); $.ajax({ type: "POST", url: "web-block/forms/process-001.php", data: dataString, success: function() { $(".save-notice").show(); $(this).parents(".manage-content-wrap").next(".ribbon-content").fadeIn(); } }); </code></pre> <p>on the other side, I have this HTML form :</p> <pre><code><form action="" id="select-block" class="general-form"> <div class="input-wrap"> <input class="clearme" name="Headline" value="<?php echo $Headline;?>" id="headline"/> </div> <div class="input-wrap"> <textarea class="clearme" name="Sub-Headline" id="subheadline"><?php echo $SubHeadline;?></textarea> </div> <label>Bottom Left Image</label> <div class="up-mask"> <span class="file-wrapper"> <input type="file" name="Pics" class="photo" id="pics" /> <span class="button"> <span class="default-txt">Upload Photo</span> </span> </span> </div> <input type="hidden" name="Key" value="<?php echo $Key;?>"/> <input type="submit" class="submit-btn" value="SAVE" /> <span class="save-notice">Your changed has been saved!</span> </form> </code></pre> <p>as you can see process-001.php is the file which process all variables from HTML form. but I have difficulties to 'catch' <code>$Headline</code> and <code>$SubHeadline</code> submitted by that form, which actually 'manipulates' by Ajax too...</p> <p>I tried using this code on process-001.php :</p> <pre><code>$Headline = $_POST['Headline']; $SubHeadline = $_POST['Sub-Headline']; </code></pre> <p>but seems that those variables are empty... how to get variables submitted by AJAX correctly?</p>
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How To Get Variables Submitted by AJAX Using PHP Correctly?
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