StackOverflow2013

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13208624
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0
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2012-11-03T11:15:37.797
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2012-11-03T15:35:40.580
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2012-11-03T15:35:40.580
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592323
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592323
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13208586
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2
Score
1
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text
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You could also do this very easy with lambdas (C++0x/11): <pre><code>vector<Character> v = ...; sort(v.begin(), v.end(), [](const Character &lhs,const Character & hs){ return lhs.getType() == rhs.getType() ? lhs.getScore() < rhs.getScore() : lhs.getType() < lhs.getType(); }); </code></pre> Or for pointers: <pre><code>vector<Character*> v = ...; sort(v.begin(), v.end(), [](const Character *lhs,const Character * hs){ return lhs->getType() == rhs.getType() ? lhs->getScore() < rhs->getScore() : lhs->getType() < lhs->getType(); }); </code></pre> <hr> I couldn't find a "criteria combiner" so I wrote one on my own. This should work: <pre><code>template<class T, class First, class Second> class combine { First first; Second second; public: bool operator()(const T & lhs, const T & rhs) const { if(first(lhs, rhs)) return true; if(first(rhs, lhs)) return false; return second(lhs, rhs); } }; </code></pre> With two basic comparison functors <pre><code>struct less_type { static bool operator()(const Character & lhs, const Character & rhs) { return lhs.getType() < rhs.getType(); } }; struct less_score { static bool operator()(const Character & lhs, const Character & rhs) { return lhs.getScore() < rhs.getScore(); } }; </code></pre> this can be used like the following: <pre><code>vector<Character*> v = ...; sort(v.begin(),v.end(), combine<Character,less_type,less_score>()); </code></pre> This will also work without support for C++0x lambdas.
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1. POC++ How to do 2 Sort and merge result into 1
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