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    <p>For starters, in JavaScript (ES5), there isn't such a thing as "Integer". JavaScript (ES5) only has Numbers. </p> <p>Second, in JavaScript there is a lot of implicit type-casting going on. Here is an example:</p> <pre><code>if(1=='1') console.log('very truthy'); </code></pre> <p>If you use a double-equals, it will cast the '1' to a Number and then it will compare the new value (1) to the 1 (which will be true, 1 == 1), and will then log the string 'very truthy'. </p> <p>If you use triple-equals, the implicit type-casting won't happen. </p> <pre><code>if(1==='1') console.log("this won't get logged"); </code></pre> <p>Using the triple-equals prevents the type casting from happening. </p> <p>Next, when you add a value to a whole number index of an array, that index gets updated with the value you tell it to, AND THE LENGTH will get updated. </p> <pre><code>var a = []; a[0] = 0 a[1] = 1; a[2.0] = 2; //[undefined, 1, 2] </code></pre> <p>When you try to update an index that isn't a whole number (1.1), it will convert whatever that is to a string (1.1 becomes '1.1') and then it adds a new custom property to the array and set's the value on it. Custom properties of an array won't affect it's length. </p> <pre><code>var a = []; a[1.1] = 1.1; a.prop = "property"; //[], empty array console.log(a.prop, a['1.1']); //"property",1.1 </code></pre> <p>When you add a custom property to a JS array it mutates the object to then act like an object literal. </p> <p>So in your case here, you end up with an array-ish/object-literal-ish mashup object. NOTE: If you add a custom property to a JS Number or String, they are NOT converted to Object Literals. This behavior that you are exploring is unique to JS arrays. </p>
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    1. POHow does JavaScript determine if an array index is integer?
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    1. COThe last paragraph made absolutely no sense to me.
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    2. CO@Musa Is there a piece of it specifically that you wanted to question about, or should we leave it at that?
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