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    <p>You could define your variable <code>searchRooms</code> as a global (or some other suitable enclosing scope), outside of the scope of your <code>.change</code> function and it would be available when you do you AJAX call. Alternatively, you can just grab the values you need when you do your AJAX call exactly the same way you are doing it in your <code>.change</code> function. </p> <p>In fact, as it stands right now, your <code>.change</code> function is doing nothing useful. You are grabbing the value from <code>#rooms</code> and putting it in a local variable that goes immediately out-of-scope. So it's not clear what you were trying to do there anyway. </p> <p>So, you could do this:</p> <pre><code>var searchRooms; $("#rooms").change(function () { searchRooms = $("#rooms").val(); }); </code></pre> <p>Or, better, you could just do this:</p> <pre><code>$("#mybutton").click(function() { var searchRooms = $("#rooms").val(); var myotherdropdown = $("#otherdropdown").val(); // now do your AJAX call, passing in your variables you grabbed above. $.ajax(//..... }); </code></pre> <p><em>Update</em>: Something like this:</p> <pre><code>var searchRooms; var searchAdults; var searchChildren; $("#rooms").change(function () { searchRooms = $("#rooms").val(); }); $("#adults").change(function () { searchAdults = $("#adults").val(); }); $("#searchChildren").change(function () { searchChildren = $("#children").val(); }); $(#"btn").click(function(){ // How you pass the data here will depend on what you are calling and what format it's expecting. It *might* look something like this... $.ajax({ data: { "searchRooms" : searchRooms, "searchAdults" : searchAdults, "searchChildren": searchChildren }, // all your other settings for this ajax call... }); }); </code></pre>
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    1. POpass three dropdown selected values as a parameters via Ajax to controller
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    1. USMatt Burland
    1. USMatt Burland
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    1. COso how to define a searchRooms variable as global variable in jquery with in button click event
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    2. COIf a variable is defined outside of any function, it's global. So, as in the first example, `searchRooms` is defined outside of the `.change` function, so it is available to every function. A somewhat better way to do this however, is if all your function live inside your `$(function(){/*...*/})`, you can define your variable inside that function and the functions enclosed by it will be able to access those variables because of *closure*
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      1. USMatt Burland
    3. COok thanx.the second way, won't work. because we cant get the value from dropdown simply using this line.var searchRooms = $("#rooms").val();. i didnt get the value actually. when i have used .change function i got the value into variable. so after three change functions,we can pass parameters via ajax call. anyway thanq :)
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