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plurals

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13111932
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2012-10-28T18:54:20.130
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2012-10-28T18:54:20.130
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In the general case, this would be really, really hard. But we can see if they've made it any easier for us. We can read in a line and look at it: <pre><code>In [31]: first_line = open("toyota.dot").readline() In [32]: print repr(first_line) ' 1\t958164\tTOYOTA MOTOR CORPORATION\tTOYOTA\tLAND CRUISER\t1994\t\t19941223\tN\t0\t0\tSERVICE BRAKES, HYDRAULIC:ANTILOCK\tARNOLD \tCA\tJT3DJ81W8R0\t19950103\t19950103\t\t\tABS SYSTEM FAILURE, AT 20MPH. TT\tEVOQ\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\tV\t\n' </code></pre> See all those <code>\t</code> symbols? We're in luck -- the columns are separated by tabs! So one way is to use the <code>.split()</code> method on the lines to break them into columns: <pre><code>In [33]: first_line.split("\t") Out[33]: [' 1', '958164', 'TOYOTA MOTOR CORPORATION', 'TOYOTA', 'LAND CRUISER', '1994', [... etc ...] '\n'] </code></pre> and we can then extract columns: <pre><code>In [34]: first_line.split("\t")[11] Out[34]: 'SERVICE BRAKES, HYDRAULIC:ANTILOCK' In [35]: first_line.split("\t")[12] Out[35]: 'ARNOLD ' </code></pre> and get rid of the spaces. <pre><code>In [36]: first_line.split("\t")[12].strip() Out[36]: 'ARNOLD' </code></pre> You can use the <pre><code>with open("toyota.dot") as data: for line in data: parts = line.split("\t") </code></pre> pattern to iterate over the lines, and the rest you should be able to piece together. [Aside: I'd actually use a <code>csv.reader</code> with <code>delimiter="\t"</code>, but that's probably a little beyond what the teacher is after.]
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1. POPython read file in DOT format and return city name list
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