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    <p>You cannot sort a <code>dict</code> because dictionary has no ordering. </p> <p>Instead, use <a href="http://docs.python.org/library/collections.html#collections.OrderedDict" rel="noreferrer"><code>collections.OrderedDict</code></a>:</p> <pre><code>&gt;&gt;&gt; from collections import OrderedDict &gt;&gt;&gt; d = {'Gears of war 3': 6, 'Batman': 5, 'gears of war 3': 4, 'Rocksmith': 5, 'Madden': 3} &gt;&gt;&gt; od = OrderedDict(sorted(d.items(), key=lambda x:x[1], reverse=True)) &gt;&gt;&gt; od OrderedDict([('Gears of war 3', 6), ('Batman', 5), ('gears of war 3', 4), ('Rocksmith', 5), ('Madden', 3)]) &gt;&gt;&gt; od.keys() ['Gears of war 3', 'Batman', 'gears of war 3', 'Rocksmith', 'Madden'] &gt;&gt;&gt; od.values() [6, 5, 4, 5, 3] &gt;&gt;&gt; od['Batman'] 5 </code></pre> <hr> <p>The "order" you see in an JSON object is not meaningful, as JSON object is unordered[<a href="http://www.ietf.org/rfc/rfc4267.txt" rel="noreferrer">RFC4267</a>]. </p> <p>If you want meaningful ordering in your JSON, you need to use a list (that's sorted the way you wanted). Something like this is what you'd want:</p> <pre><code>{ "count": 24, "top 5": [ {"Gears of war 3": 6}, {"Batman": 5}, {"Rocksmith": 5}, {"gears of war 3": 4}, {"Madden": 3} ] } </code></pre> <p>Given the same dict <code>d</code>, you can generate a sorted list (which is what you want) by:</p> <pre><code>&gt;&gt;&gt; l = sorted(d.items(), key=lambda x:x[1], reverse=True) &gt;&gt;&gt; l [('Gears of war 3', 6), ('Batman', 5), ('Rocksmith', 5), ('gears of war 3', 4), ('Madden', 3)] </code></pre> <p>Now you just pass <code>l</code> to <code>m['top5']</code> and dump it:</p> <pre><code>m["Top 5"]= l k = json.dumps(m) </code></pre>
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    1. CO@emschorsch i want to add the output dict to another dict and convert it to json response.
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    2. CO@emschorsch i edited my code above please go through it.
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    3. CO@CodeNinja JSON objects has no ordering, so you will need to use a list instead.
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