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POFind the length of a word in an array - Visual Basic
 

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  1. POFind the length of a word in an array - Visual Basic
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    <p>I have a richtextbox and I converted the words to an array, then I have code that will take the length and the output it... only problem is I don't know how to loop through all the different values of the array to check the length of each individual part of the array. </p> <p>(I have this set on TextChanged) </p> <pre><code> Dim len1, len2, len3, len4, len5, len6, len7, len8, len9, len10, len11, len12, len13, len14, len15 As Integer Dim input As String Dim words As String() Dim length As Integer input = RichTextBox1.Text words = input.Split(New String() {" "}, StringSplitOptions.RemoveEmptyEntries) For Each w In words length = Len(w) Select Case length Case 1 len1 = len1 + 1 Case 2 len2 = len2 + 1 Case 3 len3 = len3 + 1 Case 4 len4 = len4 + 1 Case 5 len5 = len5 + 1 Case 6 len6 = len6 + 1 Case 7 len7 = len7 + 1 Case 8 len8 = len8 + 1 Case 9 len9 = len9 + 1 Case 10 len10 = len10 + 1 Case 11 len11 = len11 + 1 Case 12 len12 = len12 + 1 Case 13 len13 = len13 + 1 Case 14 len14 = len14 + 1 Case 15 len15 = len15 + 1 End Select Next letcount.onelet.Text = Val(len1) letcount.twolet.Text = Val(len2) letcount.threelet.Text = Val(len3) letcount.fourlet.Text = Val(len4) letcount.fivelet.Text = Val(len5) letcount.sixlet.Text = Val(len6) letcount.sevenlet.Text = Val(len7) letcount.eightlet.Text = Val(len8) letcount.ninelet.Text = Val(len9) letcount.tenlet.Text = Val(len10) letcount.elevenlet.Text = Val(len11) letcount.twelevelet.Text = Val(len12) letcount.thirteenlet.Text = Val(len13) letcount.fourteenlet.Text = Val(len14) letcount.fifteenlet.Text = Val(len15) </code></pre>
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    1. COI'm a bit confused... What are you trying to accomplish here - Seems like there should be a much more efficient way....
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      1. USJohn Bustos
    2. COWhat did you try? I know you posted some code but I see no attempt to loop through the words.
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      1. USMeta-Knight
 

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