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POWhy does my open menuIItem dialog box open the save file dialog box?
 

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    <p>I made a small text editor that saves text from a <code>RichTextBox</code> into an <code>.rtf</code> file, but whenever I click the open menu option it opens the savefile dialog box. I cannot figure out why can anyone help me out?</p> <p>Here are the names for the menu dialog items. </p> <p>MenuStrip: <code>menuStrip1</code> Save: <code>saveMenu</code> Open: <code>openMenu</code> RichTextBox: <code>richTextBox1</code></p> <p>here is the code that I am working on below... </p> <pre><code>using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; namespace WindowsFormsApplication1 { public partial class Form1 : Form { public Form1() { InitializeComponent(); } //save the file private void menuStrip1_ItemClicked(object sender, ToolStripItemClickedEventArgs e) { // Text from the rich textbox rtfMain string str = richTextBox1.Text; // Create a new SaveFileDialog object using (SaveFileDialog dlgSave = new SaveFileDialog()) try { // Available file extensions dlgSave.Filter = "Rich Text Format (.rtf)|*.rtf"; // SaveFileDialog title dlgSave.Title = "Save"; // Show SaveFileDialog if (dlgSave.ShowDialog() == DialogResult.OK &amp;&amp; dlgSave.FileName.Length &gt; 0) { richTextBox1.SaveFile(dlgSave.FileName); } } catch (Exception errorMsg) { MessageBox.Show(errorMsg.Message); } } private void openMenu_ItemClicked(object sender, ToolStripItemClickedEventArgs e) { using (var of = new OpenFileDialog()) { of.DefaultExt = "*.rtf"; of.Filter = "RTF Files|*.rtf"; if (of.ShowDialog() == DialogResult.OK) richTextBox1.Rtf = System.IO.File.ReadAllText(of.FileName); } } } } </code></pre>
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    1. COAre you sure the open file menu item is calling the correct event handler?
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