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    <p><strong>First Answer:</strong></p> <p>This matches <code>#,###,##0.00</code>:</p> <pre><code>^[+-]?[0-9]{1,3}(?:\,?[0-9]{3})*(?:\.[0-9]{2})?$ </code></pre> <p>And this matches <code>#.###.##0,00</code>:</p> <pre><code>^[+-]?[0-9]{1,3}(?:\.?[0-9]{3})*(?:\,[0-9]{2})?$ </code></pre> <p>Joining the two (there are smarter/shorter ways to write it, but it works):</p> <pre><code>(?:^[+-]?[0-9]{1,3}(?:\,?[0-9]{3})*(?:\.[0-9]{2})?$) |(?:^[+-]?[0-9]{1,3}(?:\.?[0-9]{3})*(?:\,[0-9]{2})?$) </code></pre> <p>You can also, add a capturing group to the last comma (or dot) to check which one was used.</p> <hr> <p><strong>Second Answer:</strong></p> <p>As pointed by <strong>Alan M</strong>, my previous solution could fail to reject a value like <code>11,111111.00</code> where a comma is missing, but the other isn't. After some tests I reached the following regex that avoids this problem:</p> <pre><code>^[+-]?[0-9]{1,3} (?:(?&lt;comma&gt;\,?)[0-9]{3})? (?:\k&lt;comma&gt;[0-9]{3})* (?:\.[0-9]{2})?$ </code></pre> <p>This deserves some explanation:</p> <ul> <li><p><code>^[+-]?[0-9]{1,3}</code> matches the first (1 to 3) digits;</p></li> <li><p><code>(?:(?&lt;comma&gt;\,?)[0-9]{3})?</code> matches on optional comma followed by more 3 digits, and captures the comma (or the inexistence of one) in a group called 'comma';</p></li> <li><p><code>(?:\k&lt;comma&gt;[0-9]{3})*</code> matches zero-to-any repetitions of the comma used before (if any) followed by 3 digits;</p></li> <li><p><code>(?:\.[0-9]{2})?$</code> matches optional "cents" at the end of the string.</p></li> </ul> <p>Of course, that will only cover <code>#,###,##0.00</code> (not <code>#.###.##0,00</code>), but you can always join the regexes like I did above.</p> <hr> <p><strong>Final Answer:</strong></p> <p>Now, a complete solution. Indentations and line breaks are there for readability only.</p> <pre><code>^[+-]?[0-9]{1,3} (?: (?:\,[0-9]{3})* (?:.[0-9]{2})? | (?:\.[0-9]{3})* (?:\,[0-9]{2})? | [0-9]* (?:[\.\,][0-9]{2})? )$ </code></pre> <p>And this variation captures the separators used:</p> <pre><code>^[+-]?[0-9]{1,3} (?: (?:(?&lt;thousand&gt;\,)[0-9]{3})* (?:(?&lt;decimal&gt;\.)[0-9]{2})? | (?:(?&lt;thousand&gt;\.)[0-9]{3})* (?:(?&lt;decimal&gt;\,)[0-9]{2})? | [0-9]* (?:(?&lt;decimal&gt;[\.\,])[0-9]{2})? )$ </code></pre> <hr> <p><strong>edit 1</strong>: "cents" are now optional; <strong>edit 2</strong>: text added; <strong>edit 3</strong>: second solution added; <strong>edit 4</strong>: complete solution added; <strong>edit 5</strong>: headings added; <strong>edit 6</strong>: capturing added; <strong>edit 7</strong>: last answer broke in two versions;</p>
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    1. CO+1. I would move the anchors outside the alternation. You could move the common leading and trailing elements outside it as well, but that's not necessarily worth the tradeoff in readability
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    2. COReadability is not a strong point of regular expressions, but I agree. Thanks for the vote :)
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    3. COJust noticed, the thousands separators should *not* be optional; e.g., `(?:\.?[0-9]{3})*` should be `(?:\.[0-9]{3})*`. Otherwise, you could match things like `11,111111.00` or `1111.111,00`.
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