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POUnknown column in `where` clause
 

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    <p>I am getting the error described in title:</p> <pre><code>Unknown column 'FeedbackType' in 'where clause' </code></pre> <p>But I don't understand why. This is my query:</p> <pre><code>SELECT SQL_CALC_FOUND_ROWS `Appointments`.ID, FeedbackType, FeedbackSubType FROM `UserFeedback` INNER JOIN `Appointments` ON `Appointments`.ID = `UserFeedback`.Appointments_ID INNER JOIN `Reasons` ON `UserFeedback`.FeedbackSubType = `Reasons`.ID WHERE `FeedbackType` = 1 ORDER BY `Appointments`.ID ASC LIMIT 0, 10 </code></pre> <p><code>FeedbackType</code> is a column in the <code>UserFeedback</code> table, casing is correct, checked it several times already.</p> <p>For completeness, this is the table schema:</p> <pre><code>CREATE TABLE IF NOT EXISTS `UserFeedback` ( ID bigint(20) NOT NULL AUTO_INCREMENT, FeedbackType int(4) NOT NULL, FeedbackSubType int(4) NOT NULL, Notes varchar(170) NULL, Appointments_ID bigint(20) NOT NULL, IpTracking_ID bigint(20) NOT NULL, PRIMARY KEY (ID), FOREIGN KEY (Appointments_ID) REFERENCES Appointments(Id), FOREIGN KEY (IpTracking_ID) REFERENCES IpTracking(Id) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; </code></pre> <p>What could be the issue?</p> <p><strong>[Edit]</strong></p> <p>These variants don't work either (because <code>FeedbackType</code> does not contain reserved words/characters and belongs only to the <code>UserFeedback</code> table):</p> <pre><code>... WHERE UserFeedback.FeedbackType = 1 ... WHERE `UserFeedback`.`FeedbackType` = 1 ... WHERE FeedbackType = '1' etc. </code></pre> <p>(and I actually see no reason why they should)</p> <p><strong>[Edit 2]</strong></p> <p>I ran <code>SELECT * FROM UserFeedback</code> to make sure it really contains the column, and I got several rows, all containing the column (well, <code>INSERT</code>s worked without errors).</p> <p>For each of the mentioned variants, I always get the same error, always in the <code>WHERE</code> clause. If I omit the <code>WHERE</code> clause, I get unfiltered results (including the <code>FeedbackType</code> column in those results), so it's really confusing.</p> <p><strong>[Solution]</strong></p> <p>For some reason, replacing the <code>WHERE</code> query with a condition inside <code>INNER JOIN</code> fixed it, as @MarinSagovac <a href="https://stackoverflow.com/a/12877506/1488067">suggested in his second snippet</a>:</p> <pre><code>SELECT SQL_CALC_FOUND_ROWS `Appointments`.ID, FeedbackType, FeedbackSubType FROM `Appointments` INNER JOIN `UserFeedback` ON `Appointments`.ID = `UserFeedback`.Appointments_ID AND `UserFeedback`.FeedbackType = 1 INNER JOIN `Reasons` ON `UserFeedback`.FeedbackSubType = `Reasons`.ID ORDER BY `Appointments`.ID ASC LIMIT 0, 10 </code></pre> <p>Note that there's no <code>WHERE</code> clause now, but the semantics should be the same, right? And it's clear that the column really exists, so the error message is a bit misleading IMHO.</p>
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    1. CO@SOaddict: *Unknown column 'UserFeedback.FeedbackType' in 'where clause'* (or *Unknown column 'FeedbackType' in 'where clause'* if I omit table name).
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    2. COAre you sure the column exists? Was the table created without the column and then you added it to the sql at a later point. If so, the "if not exists" statement will prevent it from being added. Run this `SELECT * FROM UserFeedback` and tell us what columns you see in the result.
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    3. CO@JLevett: yes, tried it, it exists. I ran `SELECT * FROM UserFeedback` and it returned all 6 columns. I even manually copy/pasted the column from that output into my query to make sure I wasn't (entirely) crazy.
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