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    <p>Here's a couple things:</p> <ul> <li><p><a href="http://docs.oracle.com/javase/7/docs/api/java/lang/Character.html#isSurrogate%28char%29"><code>Character.isSurrogate(char c)</code></a>:</p> <blockquote> <p>A char value is a surrogate code unit if and only if it is either a low-surrogate code unit or a high-surrogate code unit.</p> </blockquote></li> <li><p>Checking for pairs seems pointless, why not just remove all surrogates?</p></li> <li><p><code>x == false</code> is equivalent to <code>!x</code></p></li> <li><p><a href="http://docs.oracle.com/javase/7/docs/api/java/lang/StringBuilder.html"><code>StringBuilder</code></a> is better in cases where you don't need synchronization (like a variable that never leaves local scope).</p></li> </ul> <p>I suggest this:</p> <pre><code>public static String removeSurrogates(String query) { StringBuilder sb = new StringBuilder(); for (int i = 0; i &lt; query.length(); i++) { char c = query.charAt(i); // !isSurrogate(c) in Java 7 if (!(Character.isHighSurrogate(c) || Character.isLowSurrogate(c))) { sb.append(firstChar); } } return sb.toString(); } </code></pre> <h3>Breaking down the <code>if</code> statement</h3> <p>You asked about this statement:</p> <pre><code>if (!(Character.isHighSurrogate(c) || Character.isLowSurrogate(c))) { sb.append(firstChar); } </code></pre> <p>One way to understand it is to break each operation into its own function, so you can see that the combination does what you'd expect:</p> <pre><code>static boolean isSurrogate(char c) { return Character.isHighSurrogate(c) || Character.isLowSurrogate(c); } static boolean isNotSurrogate(char c) { return !isSurrogate(c); } ... if (isNotSurrogate(c)) { sb.append(firstChar); } </code></pre>
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    1. POHow to remove surrogate characters in Java?
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    1. POHow to remove surrogate characters in Java?
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    1. COI am using Jdk 1.6.0. and I am not able to find Character.isSurrogate(c) method inbuilt. Is that something existing or did you give as an example?
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    2. CO@Slowcoder Apparently it was added in Java 7. I switched to a version that works in Java 6. You can read the statement as "not a high surrogate or a low surrogate" instead of the (more complicated in my opinion) "not a high surrogate and not a low surrogate".
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    3. COIf "c" is a low surrogate character, this code will append the character to "sb" because of the OR condition. Am I right?
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