StackOverflow2013

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plurals

PO
primarykey
Id
12863899
data
AcceptedAnswerId
0
AnswerCount
0
ClosedDate
CommentCount
1
CommunityOwnedDate
CreationDate
2012-10-12T17:06:18.480
FavoriteCount
0
LastActivityDate
2012-10-12T17:13:21.110
LastEditDate
2017-05-23T12:01:37.133
LastEditorUserId
-1
OwnerUserId
1395993
ParentId
12863527
PostTypeId
2
Score
2
ViewCount
0
LastEditorDisplayName
text
Body
Here is an <a href="https://stackoverflow.com/a/6390357/1395993">answer</a> that describes the <code>char[1]</code> trick. Basically, the idea is to allocate more memory when <code>malloc()</code>ing the struct, to already have some storage for your string without additional allocation. You can sometimes even see <code>char something[0]</code> used for the same purpose, which makes even less intuitive sense. <blockquote> On the other hand, treating this as a full blown char * doesn't work either, as can be seen with the test_s.b is output above, which should show a NULL pointer then... </blockquote> If something is an array, both its name and <code>&name</code> just give the pointer to the start of the array in C. This works regardless of whether it's a member in a struct, or a free standing variable. <pre><code>printf("real sizeof(test_s.b): %lx \n", ((void *)(&test_s.b) - (void *)(&test_s.a)) ); </code></pre> This line gives the size of space allocated for <code>a</code>, not <code>b</code> in this struct. Put something after <code>b</code> and used this to subtract. With the <code>packed</code> attribute (which means you disallow the compiler to mess with alignment, etc.), you should get 1. <pre><code>#include <stdio.h> #include <string.h> struct test_struct { char *a; char b[1]; char c; } __attribute__((packed)); int main() { struct test_struct s; printf("%lx\n", ((void*)&s.c) - ((void*)&s.b)); return 0; } </code></pre> I get <code>1</code>.
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1. POC char array as pointers
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1. USJakub Wasilewski
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1. COMany thanks for your help and the [answer](http://stackoverflow.com/questions/6390331/why-use-array-size-1-instead-of-pointer/6390357#6390357) link you've provided!
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 USgrasbueschel

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