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  1. PO
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    <p>Try this "array formula"</p> <p><code>=SUM(IF(FREQUENCY(IF(A$1:A$11=C1,IF(B$1:B$11&lt;&gt;"",MATCH(B$1:B$11,B$1:B$11,0))),ROW(B$1:B$11)-ROW(B$1)+1),1))</code></p> <p>confirmed with <code>CTRL+SHIFT+ENTER</code></p> <p>Where C1 is the first category to count for. Copy formula down for all categories</p> <p><strong>Explanation</strong></p> <p>The basic idea of the formula is that the first <code>IF</code> is a "filter" to ensure that you only look at B values if A value = C1, the second <code>IF</code> filters out blanks in B, otherwise the <code>MATCH</code> gives the position of the first match for that value in B (thus giving the same number for the same values)</p> <p>The result of the <code>IFs</code> is the first part of <code>FREQUENCY</code> function. The "bins" in <code>FREQUENCY</code> are formed by the <strong>ROW-ROW+1</strong> part which gives you a range of numbers 1 to n which will encompass the whole range of values that <code>MATCH</code> might give.</p> <p>Now we just need to count the number of different numbers returned by the <code>IF</code>s (as that will be equal to the number of different values in B for your criterion), so the final 1 in the formula is assigned to each non-zero value in <code>FREQUENCY</code> and the result is summed.</p> <p>In detail for your example where C1 = A this part</p> <p><code>=IF(A$1:A$11=C1,IF(B$1:B$11&lt;&gt;"",MATCH(B$1:B$11,B$1:B$11,0)))</code></p> <p>results in this array</p> <p><code>{1;2;2;4;FALSE;FALSE;FALSE;8;9;FALSE;FALSE}</code></p> <p>FALSE values where col A &lt;> "A" otherwise numbers from <code>MATCH</code> giving the position of the first match for each value - notice 2 appears twice because foo appears twice, firstly in row 2</p> <p>and the <code>ROW(B$1:B$11)-ROW(B$1)+1</code> part gives you this array</p> <p><code>{1;2;3;4;5;6;7;8;9;10;11}</code></p> <p>so now the formula looks like this</p> <p><code>=SUM(IF(FREQUENCY({1;2;2;4;FALSE;FALSE;FALSE;8;9;FALSE;FALSE},{1;2;3;4;5;6;7;8;9;10;11}),1))</code></p> <p>So <code>FREQUENCY</code> puts the values in the first array into the relevant "bins" and formula now resolves to this</p> <p><code>=SUM(IF({1;2;0;1;0;0;0;1;1;0;0;0},1))</code></p> <p>Note that the array returned by <code>FREQUENCY</code> sums to 6 (six rows with value "A") but there are only 5 non-zero numbers, denoting the five different values for criterion "A".</p> <p>Now the last IF returns a 1 for each non-zero value and <code>SUM</code> function sums those to get 5</p>
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    1. POHow to count unique values per category in Excel
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    1. USbarry houdini
    1. USbarry houdini
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    1. COThat worked! I will look at the formula that you gave me carefully and ask questions if I do not understand something; I'd like to be able to use these formulas on my own. Many thanks!
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      1. USLuchadeer
    2. COThis might be a bit much to ask, but could you explain briefly what you did there? I know the second `IF` looks whether or not the value is `C1`, then it reurns that value only if any of those rowns arent blank ( `IF(B$1:B$11<>"",...`). However, I am confused about what the `ROW` funcitons are doing there. Either Way, thanks a lot, this worked
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      1. USLuchadeer
    3. COI posted an explanation in my answer.....
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      1. USbarry houdini
 

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