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POHow to write ANSI compatible bytes in Python 3 (0x80 and up)?
 

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  1. POHow to write ANSI compatible bytes in Python 3 (0x80 and up)?
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    <p>I am new to python and try to write a script which makes byte 0x00-0xff output to a file.</p> <p>This is the code i am currently looking at</p> <pre><code>import sys filename="binarywriter.txt" openmode="wb" charset="utf8" file=open(filename, openmode) for x in range(16,256): s="0x%.2x=\\x" %x s+=hex(x)[2:] d=bytes(s, charset).decode("unicode_escape") file.write(d.encode(charset)) file.write("\r\n".encode(charset)) file.close() sys.stdin.readline() </code></pre> <p>The thing is that the python script writes all well until byte 0x7f (which is ascii) after this (0x80) it converts all output in utf8 encoding which has 2 bytes. The thing is to avoid this and only write something like this:</p> <pre><code>... 0x7f 0x80 0x81 ... </code></pre> <p>so i need something like 8bit encoding but after hour of searching there has not been any result for me</p> <p>there is also a little problem, where numbers &lt;16 return a single hex value which cannot be decoded, but i might find a solution for this</p>
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