StackOverflow2013

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12702362
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2012-10-03T05:25:05.023
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2012-10-03T05:25:05.023
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That needs three slightly different answers: <ol> <li>Yes, you can wrap an exception in another exception of the same type.</li> <li>No, you can't wrap an exception in itself (i.e. in the exact same instance).</li> <li>Unfortunately yes, you can create a loop (A causing B causing A causing B ...).</li> </ol> The first one is pretty clear: you can wrap an <code>IllegalStateException</code> wrapping an <code>IllegalArgumentException</code> caused by another <code>IllegalStateException</code>. The second one is prevented by the code in <code>initClause()</code> (which is called by the constructor or can be called directly if it was never called before), that prevents self-causation (indeed <code>cause == this</code> is used as a flag that no cause was set, to distinguish it from <code>cause == null</code> which means the cause was explicitly set to <code>null</code>). The third bit is bad, but shouldn't happen too often in practice, as you'd have to do some extra work to get it: <pre><code>Exception e1 = new Exception(); Exception e2 = new Exception(e1); e1.initCause(e2); </code></pre> Luckily <code>printStackTrace()</code> actually handles that case: <pre><code>java.lang.Exception: java.lang.Exception at ScratchMain.main(ScratchMain.java:6) Caused by: java.lang.Exception at ScratchMain.main(ScratchMain.java:5) [CIRCULAR REFERENCE:java.lang.Exception: java.lang.Exception] </code></pre>
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1. POCan we wrap an Exception with its own in java
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1. PTAnswer
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1. USJoachim Sauer
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