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    <p>If the return value of a function is an object that has a method, you can call that method immediately. Simple as that.</p> <p>Since you're returning <code>this</code>, you're returning the same object that the previous method was called on. That means you're returning an object with all the same methods.</p> <hr> <p>Think of it this way:</p> <pre><code>var f = { foo: function() { console.log("foo"); return b; } }; var b = { bar: function() { console.log("bar"); return f; } }; </code></pre> <p>Here we have two objects. </p> <ul> <li>The <code>f</code> object has a method called <code>foo</code> that returns the <code>b</code> object.</li> <li>The <code>b</code> object has a method called <code>bar</code> that returns the <code>f</code> object.</li> </ul> <p>Because of this, after calling <code>foo</code>, we can call <code>bar</code>, and vice versa.</p> <pre><code>f.foo().bar().foo().bar(); // etc </code></pre> <p>But because <code>f</code> doesn't have <code>bar</code> and <code>b</code> doesn't have <code>foo</code>, we can never call the same method twice.</p> <hr> <p>But what if we only had one object, that had both methods, and both methods always returned the same original object?</p> <pre><code>var fb = { foo: function() { console.log("foo"); return fb; }, bar: function() { console.log("bar"); return fb; } }; </code></pre> <p>Now we're always returning an object that has both the <code>foo</code> and <code>bar</code> methods, so we can call either method.</p> <pre><code>fb.foo().bar().bar().bar().foo().foo().bar(); </code></pre> <p>So now the only real difference is that we are returning <code>fb</code> instead of <code>this</code>, but it doesn't matter since they're the same object. The code above could do <code>return this;</code> and it would behave the same.</p> <p>It would matter if you wanted to create several instances of the object, but <strong><em>that's a question of object orientation techniques, not method chaining</em></strong>.</p>
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    1. POI am not able to understand how jQuery chaining works
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    1. COThis explains chaining within a singleton, but it’s not how jQuery works at all.
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    2. CO@David: Prototypal inheritance is how jQuery associates methods with the objects it creates. That has nothing to do with chaining. jQuery's chaining is done by returning `this`, which is a reference to the calling context object. Prototypal inheritance is not required for chaining, or for returning `this`.
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    3. COWell, the question was about how "jQuery chaining works", not chaining in general.
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