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    <blockquote> <p><em>i need full path to upload a file in mysql db.</em></p> </blockquote> <p>There's a major thinking mistake here.</p> <p>Imagine that <em>I</em> am the client who want to upload the file and that <em>you</em> are the server who need to get the file's contents. I give you my full local disk file system path <code>c:\path\to\sample.docx</code> as the sole information, exactly as you requested. How would you as being the server ever get its <em>contents</em>? Do you have an open TCP/IP connection to my local hard disk file system? Really?</p> <p>This isn't how uploading files works. This would only ever work if the server runs at <em>physically the same</em> machine as the client, so that you can just use <code>FileInputStream</code> with that path. This would thus only ever work in the local development environment, but definitely not in real world production where the server runs at a physically different machine than the client, separated by a HTTP connection.</p> <p>You should instead be interested in the sole file <em>contents</em> which the client has sent to you along with the HTTP request body. In HTML terms, you can use <code>&lt;input type="file"&gt;</code> for this in a <code>&lt;form enctype="multipart/form-data"&gt;</code>. A more detailed answer with full code examples can be found here: <a href="https://stackoverflow.com/questions/2422468/how-to-upload-files-to-server-using-jsp-servlet/2424824#2424824">How to upload files to server using JSP/Servlet?</a> It describes the modern Servlet 3.0 way using <code>request.getPart()</code> and the previously defacto standard Apache Commons FileUpload API.</p> <p>Once you've implemented it the right way, you should ultimately end up with an <code>InputStream</code> representing the file contents which you obtained from the Servlet 3.0 <code>part.getInputStream()</code> or the Apache Commons FileUpload <code>item.getInputStream()</code>. You can then just use <a href="http://docs.oracle.com/javase/6/docs/api/java/sql/PreparedStatement.html#setBinaryStream%28int,%20java.io.InputStream%29" rel="nofollow noreferrer"><code>PreparedStatement#setBinaryStream()</code></a> the usual way to store it in the DB and <a href="http://docs.oracle.com/javase/6/docs/api/java/sql/ResultSet.html#getBinaryStream%28java.lang.String%29" rel="nofollow noreferrer"><code>ResultSet#getBinaryStream()</code></a> to retrieve it from the DB.</p>
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    1. COThank you for your response. its working fine .
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