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PONullPointerException on first thread
 

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    <p>EDIT:</p> <p>After making all the changes you suggested, the problem remained. The debugger said the lemma variable was null, but the fixes I applied didn't make things better. So, due to deadline issues, I decided to approach the problem from another view. Thank you all for your help. :)</p> <p>I am writing a small program and a <code>NullPointerException</code> drives me crazy. I have two classes: <code>SystemDir</code> and <code>Search</code>. The first one is just an encapsulation of initial directory and a search lemma. The <code>Search</code> class is shown below. Briefly, I want one thread to search the first level directory and the other one to expand the subdirectories. That's where I get the exception. The exception string is </p> <pre><code>Exception in thread "Thread-0" java.lang.NullPointerException at Search.searchFiles(Search.java:59) at Search.&lt;init&gt;(Search.java:53) at SystemDir.&lt;init&gt;(SystemDir.java:61) at Search$1.run(Search.java:45) at java.lang.Thread.run(Thread.java:679) </code></pre> <p>Where the 3 points are t.start() inside the final loop, searchFiles method call, some lines above and the new SystemDir call in the run method. Can you help me please?</p> <pre><code>public class Search { private Thread t; public Search(String[] subFiles, final String[] subDir, final String lemma) { t = new Thread(new Runnable() { @Override public void run() { for(int i=0;i&lt;subDir.length;i++) { try { System.out.println(subDir[i]); new SystemDir(subDir[i], lemma); } catch (NoDirectoryException ex) { Logger.getLogger(Search.class.getName()).log(Level.SEVERE, null, ex); } } } }); searchFiles(subFiles,lemma); } private void searchFiles(String[] subFiles, String lemma) { for(int i=0;i&lt;subFiles.length;i++) { t.start(); if(subFiles[i].contains(lemma)) { System.out.println(subFiles[i]); } } } } </code></pre>
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    1. COWhen you are asking questions about an exception, always provide the actually exception, the first couple of lines, and point out _which_ line corresponds to the exception line number. Please edit your post to provide this information.
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    2. COYou 're right :)
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    3. COCan you format your code properly? It's really hard to follow when your indentation is all over the map.
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      1. USMark Peters
 

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