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    <p>chage <strong>accept="application/json"</strong> to <strong>enctype="application/json"</strong> on your HTML form.</p> <p>Spring can not parse you post data for you did not set the current headers. When use @RequestBody the default accept enctype is application/json. try to one of this:</p> <ol> <li>set post headers="content-type=application/json" on you html form or js post function.</li> <li>set you controller to accept headers="content-type=application/x-www-form-urlencoded".</li> </ol> <p>Edit</p> <p>The enctype must the same as headers. Ok, the code now looks like one of those:</p> <pre><code>// the one @RequestMapping(value = "save", method = RequestMethod.POST) public @ResponseBody UserResponse save(@RequestBody User user) throws Exception { UserResponse userResponse = new UserResponse(); return userResponse; } &lt;/form&gt; &lt;form action="/webapp/history/save" method="POST" enctype="application/x-www-form-urlencoded"&gt; &lt;input name="userId" value="user"&gt; &lt;input name="location" value="location"&gt; &lt;input name="emailAddress" value="hello@hello.com"&gt; &lt;input name="commitMessage" value="I"&gt; &lt;input type="submit" value="Submit"&gt; &lt;/form&gt; // the other @RequestMapping(value = "save", method = RequestMethod.POST, headers = {"content-type=application/x-www-form-urlencoded"}) public @ResponseBody UserResponse save(@RequestBody User user) throws Exception { UserResponse userResponse = new UserResponse(); return userResponse; } &lt;/form&gt; &lt;form action="/webapp/history/save" method="POST" enctype="application/json"&gt; &lt;input name="userId" value="user"&gt; &lt;input name="location" value="location"&gt; &lt;input name="emailAddress" value="hello@hello.com"&gt; &lt;input name="commitMessage" value="I"&gt; &lt;input type="submit" value="Submit"&gt; &lt;/form&gt; </code></pre> <p>Try one of those above.</p> <blockquote> <p>I get the following error:</p> <p>HTTP Error 415: The server refused this request because the request entity is in a format not supported by the requested resource for the requested method ().</p> </blockquote>
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    1. CO+1, this is an option as well.
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    2. COSo if I follow step 2 then Spring will detect the JSON sent and deserialize in the Object? If I follow this approach, will the code be in JSP: <form action="/webapp/history/save" method="POST" accept="application/json"> <input name="userId" value="Hello"> <input name="location" value="location"> <input name="emailAddress" value="hello@hello.com"> <input name="commitMessage" value="I"> <input type="submit" value="Submit"> </form>
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    3. COOk, the code now looks like this:
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Detail views are divided into sections. All the information in the data section comes from columns in the selected row. The other sections display data from other, related rows.

Related data can be related in a to-one or a to-many fashion. Captions of data related in a to-many fashion link to a list view showing a filtered view of the table.

Try moving around until you find a non-empty to-many entry and click on the label to get to one. You can move back to the root by clicking on the database name in the header.

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