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POAndroid: unable to maintain session after logging in the application
 

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  1. POAndroid: unable to maintain session after logging in the application
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    <p>I am trying to open up a URL in <code>WebView</code> but i am unable to do so and i think that is because the session is not maintained. I am sending the username, password and the id of user to the server in an activity. here's the code ..</p> <pre><code>public class ServiceActivity extends Activity { private Button button_back; private Button button_submit_user_pass; private EditText edit_id_code; private String contents; private String format; private String username; private String password; private String id; public static HttpClient client; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.qr_code_view); edit_id_code = (EditText) findViewById(R.id.editText_id); button_back = (Button) findViewById(R.id.button_back); button_submit_user_pass = (Button) findViewById(R.id.button_submit_user_pass); Intent user_pass = getIntent(); username = user_pass.getStringExtra("user"); password = user_pass.getStringExtra("pass"); button_submit_user_pass .setOnClickListener(user_pass_qr_submit_listener); button_back.setOnClickListener(back_listener); } private View.OnClickListener user_pass_qr_submit_listener = new View.OnClickListener() { @Override public void onClick(View v) { // TODO Auto-generated method stub try { id = edit_id_code.getText().toString(); client = new DefaultHttpClient(); HttpPost post1 = new HttpPost( "xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx"); List&lt;NameValuePair&gt; nvp = new ArrayList&lt;NameValuePair&gt;(); nvp.add(new BasicNameValuePair("uname", username)); nvp.add(new BasicNameValuePair("password", password)); nvp.add(new BasicNameValuePair("id", id)); post1.setEntity(new UrlEncodedFormEntity(nvp)); HttpResponse resp = client.execute(post1); String responseText = inputStreamTOString( resp.getEntity().getContent()).toString(); Log.i("response", responseText); int num = Integer.parseInt(responseText); if (num == 0) { Toast.makeText(getApplicationContext(), "Response" + responseText, 0).show(); } else if (num == 1) { Intent survey = new Intent(ServiceActivity.this, WebViewActivity.class); startActivity(survey); } } catch (Exception e) { Log.e("error", "ERROR" + e); } } }; private View.OnClickListener back_listener = new View.OnClickListener() { @Override public void onClick(View v) { // TODO Auto-generated method stub } }; private StringBuilder inputStreamTOString(InputStream is) { String line = ""; StringBuilder total = new StringBuilder(); // read response until the end try { BufferedReader rd = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8); while ((line = rd.readLine()) != null) { total.append(line); } } catch (Exception e) { // TODO: handle exception } return total; } } </code></pre> <p>After this if the response from the server side is "1" i am opening a new activity in which I need to display the content of the user in the <code>WebView</code> here's the code</p> <pre><code>public class WebViewActivity extends Activity{ private WebView web; @Override public void onCreate(Bundle savedInstanceState){ super.onCreate(savedInstanceState); setContentView(R.layout.web_view); web = (WebView) findViewById(R.id.webView); web.getSettings().setJavaScriptEnabled(true); web.loadUrl("xxxxxxxxxxxxxxxxxxxxxxxxxxxx"); } } </code></pre> <p>but i am unable to load the URL corresponding o the user, I get php errors over the webviewactivity and that is because i am unable to maintain the session of the user who has logged in. Please suggest me some solution to this. </p>
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    1. PO
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    1. USArshdeep_somal
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    1. PO
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    2. PO
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