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PODeferred object returned before it is rejected or resolved?
 

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    <p>I have a function that basically looks like this:</p> <pre><code>function defTest() { var dfd = new jQuery.Deferred(); $.ajax( { type: "GET", url: 'http://XXXX', cache: false, dataType: "json", success: function(data,status) { console.log('ajax done: success'); dfd.resolve(); }, error: function(data,status) { console.log('ajax done: fail'); dfd.reject(); } }); console.log('about to return dfd'); return dfd; } </code></pre> <p>I call it like this:</p> <pre><code>defTest().then(.....); </code></pre> <p>The console log produce this: about to return dfd code.js:106 ajax done: success code.js:96</p> <p>What confuses me is that the code seems to work. Still the dfd is returned BEFORE the ajax has finished. So i removed the return dfd. And put it last in each ajax handler function to make sure that this will NOT be returned until the Ajax has finished.:</p> <pre><code>success: function(data,status) { console.log('ajax done: success'); dfd.resolve(); return dfd; } </code></pre> <p>Then it didn´t work at all. I am confused! Can someone explain to me why my deferred can´t be in the ajax success and error handlers and why it works even though it seems that my deferred object returns even if it is fired BEFORE the Ajax is finished and then be resolved or rejected? How is that even possible?</p> <p>EDIT: This issue is directly linked to my previous unanswered and more complex function: <a href="https://stackoverflow.com/questions/12365568/problems-with-deferred-object">Problems with deferred object</a></p> <p>This is why i can´t just "return ajax(...)" because my real function contains other ajax calls that will be apart of ONE result handed back to the caller.</p>
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    1. USJuw
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    1. CO[XY problem](http://meta.stackexchange.com/questions/66377/what-is-the-xy-problem). You can't return an asynchronous action result from your function which seems like what you're trying to do.
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      1. USFabrício Matté
    2. COThat is what i am trying to solve using deferred objects.
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    3. CO`$.ajax` already returns a deferred object as xdazz answered. JavaScript is single-threaded, function calls are synchronous and must return a value (or nothing) synchronously. `$.ajax` is asynchonous. What you can (and should) do is use the ajax success callback to do what you have to do when the ajax request is completed.
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      1. USFabrício Matté
 

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