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    <p>There are 2 ways to achieve what you're looking for:</p> <p>1) To show the selected item at the top of the dropdown</p> <pre><code>echo "&lt;select name='itemgroupid'&gt;"; // CHOOSE CURRENT SET RECORD AS SELECTED ITEM echo "&lt;option value='" . $itemgroupid . "'&gt;"; $selected=" SELECT item.itemid, itemgroup.itemgroupname, itemgroup.itemgroupid FROM item, itemgroup WHERE item.itemid=$itemid"; $selectedresult=mysql_query($query) or die("query fout " . mysql_error() ); while($record=mysql_fetch_array($selectedresult) ) { echo "" . $itemgroupname . "&lt;/option&gt;"; } // QUERY TO SHOW ALL POSSIBLE CHOOSABLE RECORDS FROM DATABASE $itemgroupquery="SELECT itemgroupname,itemgroupid FROM itemgroup WHERE item.itemid != $itemid"; $itemgroupqueryresult = mysql_query ($itemgroupquery); while($nt=mysql_fetch_array($itemgroupqueryresult)){ echo "&lt;option value=$nt[itemgroupid]&gt;$nt[itemgroupname]&lt;/option&gt;"; } echo "&lt;/select&gt;"; </code></pre> <p>2) Show the selected item in it natural place</p> <pre><code>echo "&lt;select name='itemgroupid'&gt;"; // QUERY TO SHOW ALL POSSIBLE CHOOSABLE RECORDS FROM DATABASE $itemgroupquery="SELECT itemgroupname,itemgroupid FROM itemgroup"; $itemgroupqueryresult = mysql_query ($itemgroupquery); while($nt=mysql_fetch_array($itemgroupqueryresult)){ echo "&lt;option value=$nt[itemgroupid]"; if( $itemid == $nt['itemgroupid'] ) echo ' selected="selected"'; echo "&gt;$nt[itemgroupname]&lt;/option&gt;"; } echo "&lt;/select&gt;"; </code></pre> <p>HTH</p>
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