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POPlotting career path in graph
 

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  1. POPlotting career path in graph
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    <p>I have the dataframe</p> <pre><code>test &lt;- structure(list( y2002 = c("freshman","freshman","freshman","sophomore","sophomore","senior"), y2003 = c("freshman","junior","junior","sophomore","sophomore","senior"), y2004 = c("junior","sophomore","sophomore","senior","senior",NA), y2005 = c("senior","senior","senior",NA, NA, NA)), .Names = c("2002","2003","2004","2005"), row.names = c(c(1:6)), class = "data.frame") &gt; test 2002 2003 2004 2005 1 freshman freshman junior senior 2 freshman junior sophomore senior 3 freshman junior sophomore senior 4 sophomore sophomore senior &lt;NA&gt; 5 sophomore sophomore senior &lt;NA&gt; 6 senior senior &lt;NA&gt; &lt;NA&gt; </code></pre> <p>and I want to create a graph that should resemble the ugly text art below:</p> <pre><code>freshman ---- junior ----------------------\ freshman ---- junior --- sophomore -------- senior sophomore ================================/ senior ---------------------------------/ </code></pre> <p>In other words, I need to show in a graph the possible paths to "senior", giving weights to edges according to the number of cases using that path.</p> <p><strong>First attempt</strong> This code generates a graph, <em>but not one similar to the text art above</em>.</p> <pre><code>library(igraph) elist &lt;- lapply(seq_len(nrow(test)), function(i) { x &lt;- as.character(test[i,]) x &lt;- unique(na.omit(x)) x &lt;- rep(x, each=2) x &lt;- x[-1] x &lt;- x[-length(x)] r &lt;- matrix(x, ncol=2, byrow=TRUE) if (nrow(r) &gt; 0) { r &lt;- cbind(r, i) } else { r &lt;- cbind(r, numeric()) } r }) result &lt;- as.data.frame(do.call(rbind, elist)) names(result) &lt;- c("vertex","edge", "id") categories &lt;- data.frame(name=c("freshman","junior","sophomore","senior")) g &lt;- graph.data.frame(result,directed=T,vertices=categories) g &lt;- set.edge.attribute(g, "weight", value=runif(ecount(g))*10) igraph.par("plot.layout", layout.reingold.tilford) plot(g, vertex.label=categories$name, vertex.label.dist=7, edge.width=get.edge.attribute(g,"weight"), edge.arrow.size=1.5) </code></pre> <p><strong>Result</strong> (not what I wanted)</p> <p><img src="https://i.stack.imgur.com/H1Gqp.png" alt="resulting image"></p> <p>**This question is related to <a href="https://stackoverflow.com/questions/12362866/from-dataframe-to-vertex-edge-array/12382276#12382276">this post</a>*</p> <p>**And <a href="https://stackoverflow.com/questions/12417467/reduce-row-to-unique-items/12418321">this post</a> is a necessary step for solving this question*</p>
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    1. USdmvianna
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    1. COYour code works, except the labels aren't printed properly and you get an error. Is your question how to remove the error?
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    2. COI don't get an error, so maybe I didn't paste the code correctly. No, my problem is that the graph I get is not like the graph in my text art.
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    3. COPS the error in you code is because the data frame you provide has `NA` values which get read into the graph as nodes. These nodes are not in your `categories`
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      1. USuser1317221_G
 

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