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2012-09-06T15:14:33.450
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2012-09-06T15:14:33.450
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I think I found the solution. Going through the example I quoted on my ask, and also the boost documentation <a href="http://www.boost.org/doc/libs/1_51_0/libs/python/doc/v2/class.html" rel="nofollow">here</a>, I figured that the problem is that the callback class is the real class being wrapped by Boost.Python, and that it has to be a concrete class. So I implemented in it the missing pure virtual methods: <pre><code>class VAlgorithm_callback: public VAlgorithm { public: VAlgorithm_callback(PyObject *p, const char *name) : self(p), VAlgorithm(name) { } virtual bool Initialize() { return call_method<bool>(self, "Initialize"); } virtual bool Process() { return call_method<bool>(self, "Process"); } virtual bool Finalize() { return call_method<bool>(self, "Finalize"); } const char * GetName() const { return call_method<const char *>(self, "GetName"); } // Supplies the default implementation of GetName static const char * GetName_default(const VAlgorithm& self_) { return self_.VAlgorithm::GetName(); } private: PyObject *self; }; </code></pre> and also modified the wrapper as: <pre><code>class_<VAlgorithm, boost::shared_ptr<VAlgorithm_callback>, boost::noncopyable ("VAlgorithm", init<const char *>()) // .def("Initialize", &VAlgorithm_callback::Initialize) .def("Process", &VAlgorithm_callback::Process) .def("Finalize", &VAlgorithm_callback::Finalize) .def("GetName", &VAlgorithm_callback::GetName_default); </code></pre> Now I can define a child class in Python and call the default GetName() method: <pre><code>>>> class ConcAlg(VAlgorithm): ... pass ... >>> c = ConcAlg("c") >>> c.GetName() 'c' >>> </code></pre>
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1. POExtending a virtual C++ class exposed via Boost.Python
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1. USNicola Mori
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