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    <p>You could make use of lambdas for such cases:</p> <pre><code> const int x = []() -&gt; int { int t; std::cin &gt;&gt; t; return t; }(); </code></pre> <p>(Note the extra () at the end).</p> <p>Instead of writing a separate functions, this has the advantage of not having to jump around in your source file, when reading the code.</p> <p><s><strong>Edit:</strong> Since in the comments it was stated that this goes against the DRY rule, you could take advantage of <code>auto</code> and <code>5.1.2:4</code> to reduce type repetition:</p> <p><code>5.1.2:4</code> states:</p> <blockquote> <p>[...] If a lambda-expression does not include a trailing-return-type, it is as if the trailing-return-type denotes the following type:</p> <ul> <li><p>if the compound-statement is of the form</p> <p><code>{ attribute-specifier-seq(opt) return expression ; }</code></p> <p>the type of the returned expression after lvalue-to-rvalue conversion (4.1), array-to-pointer conversion (4.2), and function-to-pointer conversion (4.3);</p></li> <li><p>otherwise, void.</p></li> </ul> </blockquote> <p>So we could alter the code to look like this:</p> <pre><code> const auto x = [] { int t; std::cin &gt;&gt; t; return t; }(); </code></pre> <p>I can't decide if that is better though, since the type is now "hidden" within the lambda body...</s></p> <p><strong>Edit 2:</strong> In the comments it was pointed out, that just removing the type name where it is possible, does not result in a "DRY-correct" code. Also the trailing-return-type deduction in this case is currently actually an extension of MSVC++ as well as g++ and not (yet) standard.</p>
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    1. POAre there any tricks to use std::cin to initialize a const variable?
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    1. COHm, can you skip the first set of `()` just after the `[]`?
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    2. CO@Bartek: Not if you want to provide a trailing return type.
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    3. COwow, I like lambda expressions a lot... but that just looks ugly! (Not a comment on the quality of the answer at all just how the code ends up looking visibly)
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