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plurals

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Id
12264130
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2012-09-04T13:06:58.620
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2012-09-04T13:22:46.473
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2012-09-04T13:22:46.473
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PostTypeId
2
Score
2
ViewCount
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LastEditorDisplayName
text
Body
Since you didn't specify your RDBMS, I will just assume it's Postgresql ;-) <pre><code>select *, sum(amount) over() - sum(amount) over(order by amount) as remainder from tbl; </code></pre> Output: <pre><code>| ID | AMOUNT | REMAINDER | --------------------------- | 3 | 1 | 10 | | 2 | 2 | 8 | | 1 | 3 | 5 | | 4 | 5 | 0 | </code></pre> How it works: <a href="http://www.sqlfiddle.com/#!1/c446a/5" rel="nofollow">http://www.sqlfiddle.com/#!1/c446a/5</a> It works in SQL Server 2012 too: <a href="http://www.sqlfiddle.com/#!6/c446a/1" rel="nofollow">http://www.sqlfiddle.com/#!6/c446a/1</a> Thinking of solution for SQL Server 2008... <hr/> Btw, is your ID just a mere row number? If it is, just do this: <pre><code>select row_number() over(order by amount) as rn , sum(amount) over() - sum(amount) over(order by amount) as remainder from tbl order by rn; </code></pre> Output: <pre><code>| RN | REMAINDER | ------------------ | 1 | 10 | | 2 | 8 | | 3 | 5 | | 4 | 0 | </code></pre> But if you really need the ID intact and move the smallest amount on top, do this: <pre><code>with a as ( select *, sum(amount) over() - sum(amount) over(order by amount) as remainder, row_number() over(order by id) as id_sort, row_number() over(order by amount) as amount_sort from tbl ) select a.id, sort.remainder from a join a sort on sort.amount_sort = a.id_sort order by a.id_sort; </code></pre> Output: <pre><code>| ID | REMAINDER | ------------------ | 1 | 10 | | 2 | 8 | | 3 | 5 | | 4 | 0 | </code></pre> See query progression here: <a href="http://www.sqlfiddle.com/#!6/c446a/11" rel="nofollow">http://www.sqlfiddle.com/#!6/c446a/11</a>
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1. This table or related slice is empty.
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1. POHow can I calculate the remaining amount per row?
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1. PTAnswer
UserLastEditorUserId
1. USMichael Buen
UserOwnerUserId
1. USMichael Buen
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2. VO
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1. COI actually left out one more specification: I am sorting these amounts by an outside key. There would be another integer id to divide them up by. Critical to forget I know, but being able to use it in a CTE solves another part of my problem. Thank you.
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 USuser1281598

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A row detail

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