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    <p>When you have mask-based enums, you check whether that enum is satisfied or not using the bit-wise AND operator <code>&amp;</code>.</p> <p>So, if you want to check if the skills are fast AND smart, do it like so:</p> <pre><code>if ((skills &amp; fast) &amp;&amp; (skills &amp; smart)) { // this team has the brains and speed.. possible other stuff } </code></pre> <p>Alternatively, in this situation, the XOR operator would also be a good candidate:</p> <pre><code>if (skills ^ (fast | smart) == 0) { // this team has ONLY the brains and speed. } </code></pre> <p>Last Note:</p> <p>Define the enums like this, much easier:</p> <pre><code>typedef enum { fast = 1 &lt;&lt; 0, slow = 1 &lt;&lt; 1, strong = 1 &lt;&lt; 2, smart = 1 &lt;&lt; 3, agile = 1 &lt;&lt; 4, } Skills; </code></pre> <hr /> <p><strong>EDIT:</strong></p> <p>OK, since this is an assignment, let me go through some trouble explaining how this works:</p> <p>As am sure you know, your enums look something like this (Binary):</p> <pre><code>(00001) (00010) ... (10000) </code></pre> <p>Now, using the bit-wise OR operator <code>|</code>, you were able to merge two skills together:</p> <pre><code> 00001 OR 01000 _____ 01001 </code></pre> <p>Then, we can check if that new multi-skill enum has some specific skill using <code>&amp;</code>:</p> <pre><code> 01001 AND 01000 _____ 01000 != 0 (aka true) </code></pre> <p>To go to a more advance level, we use XOR, which by definition, sets the resulting bit to <code>0</code> if the two bits are equal:</p> <pre><code> 01001 XOR 01000 _____ 00001 != 0 (aka true) 01001 XOR 01001 _____ 00000 == 0 (aka false) </code></pre>
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    1. POWrite and use a function that takes a mask as an argument and returns a structure
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    1. USMazyod
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    1. COIt should also be mentioned that `nil` is not the correct return type to indicate "no structure".
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      1. USJosh Caswell
    2. COThis is a very good answer!
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