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    <h2>Update</h2> <p>To get an array of files inside a zip, they must first be extracted into a temporary location:</p> <pre><code>import java.util.zip.*; import java.io.File; import java.util.ArrayList; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.InputStream; import java.util.Enumeration; import java.io.IOException; public class ZipFileExtractor { public static void main(String[] args) { File[] zipFiles = ZipFileExtractor.getFileArray("archive.zip"); System.out.println(zipFiles.length); } public static File[] getFileArray(String archiveFileName) { ArrayList&lt;File&gt; zipArrayList = new ArrayList&lt;File&gt;(); try { ZipFile zFile = new ZipFile(archiveFileName); for (Enumeration&lt;? extends ZipEntry&gt; e = zFile.entries(); e.hasMoreElements(); ) { ZipEntry zEntry = e.nextElement(); InputStream in = zFile.getInputStream(zEntry); File temp = File.createTempFile(zFile.getName(), null); temp.deleteOnExit(); FileOutputStream out = new FileOutputStream(temp); byte[] buffer = new byte[1024]; while (in.read(buffer) != -1) { out.write(buffer); } zipArrayList.add(temp); } } catch (IOException e) { } return zipArrayList.toArray(new File[zipArrayList.size()]); } } </code></pre> <p>&nbsp;</p> <hr> <p>&nbsp;</p> <p>There is an API class called <a href="http://docs.oracle.com/javase/6/docs/api/java/util/zip/ZipInputStream.html" rel="nofollow">ZipInputStream</a> in <code>java.util.zip</code> package.</p> <p>It has a bunch of methods, among them <code>getNextEntry()</code> that pretty much does it:</p> <pre><code>ArrayList&lt;ZipEntry&gt; zipArrayList = new ArrayList&lt;ZipEntry&gt;(); ZipInputStream zis = ZipInputStream(new FileInputStream("archive.zip")); while ((ZipEntry ze = zis.getNextEntry()) != null) { zipArrayList.add(ze.getName()); } </code></pre> <p>I haven't tried compiling the above code, so it might have a few issues but I hope the idea is clear.</p>
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    1. POHow can I get the files on a zip as a Files[] array?
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    1. USSaul
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    1. COAs I said I need a file array, not a zipentry arraylist
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    2. COYou might want to wrap that into a BufferedInputStream to speed up things a bit.
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      1. USThomas Johan Eggum
    3. CO@zyngawow - Take a look at the update.
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