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POHow to mock a base class with python mock library
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12219967
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12220965
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2012-08-31T17:26:09.217
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2014-07-04T15:25:52.687
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2012-09-01T12:07:14.660
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I try to use <code>mock</code> to write some unit-tests in python. For example I have the following class: <pre><code>class TCPHandler(socketserver.BaseRequestHandler): def handle(self): self.data = self.request.recv(1024).strip() </code></pre> And I only want to test the <code>handle</code> method. Without having to assume anything about <code>socketserver.BaseRequestHandler</code>. I for example want to assert that <code>handle</code> calls <code>recv</code> with the argument <code>1024</code>. Is it possible to do such thing with mock? I.e. replacing the base class <code>socketserver.BaseRequestHandler</code> with a mock? Or am I off track with that idea? <hr> With the answer of ecatmur (thank you!) I first tried the following: <pre><code>patcher = patch.object(TCPHandler, '__bases__', (Mock,)) with patcher: patcher.is_local = True handler = TCPHandler() handler.handle() </code></pre> But now <code>handle</code> is not called anylonger and <code>dir(handler)</code> gives: <pre><code>['assert_any_call', 'assert_called_once_with', 'assert_called_with', 'assert_has_calls', 'attach_mock', 'call_args', 'call_args_list', 'call_count', 'called', 'configure_mock', 'method_calls', 'mock_add_spec', 'mock_calls', 'reset_mock', 'return_value', 'side_effect'] </code></pre> <code>type(handler)</code> gives <code><class 'mock.TCPHandler'></code> Which I interpret that patching the base class also turns my derived class into a mock. <hr> I now gave another idea a try: <pre><code>mock = MagicMock() TCPHandler.handle(mock) #assertions </code></pre> However the mock seems not to be called.
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<python><mocking>
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How to mock a base class with python mock library
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