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    <p>In the below example <code>static int count1 = 0;</code> is initialization(assigning values at declaration). And <code>count1++;</code> is equivalent to <code>count1 = count1 + 1;</code> and this is assignment not initialization. </p> <p>While calling <code>count</code> function first time <code>static int count1 = 0;</code> will be executed and 0 will be assigned, and also <code>count1++</code> will also assign <code>1</code> to the staitc variable <code>count1</code>. While calling <code>count</code> function second time <code>static int count1 = 0;</code> will not be executed and <code>count1++</code> will be executed and <code>2</code> will be assigned to <code>count1</code>.</p> <pre><code>void count(void) { static int count1 = 0; int count2 = 0; count1++; count2++; printf("\nValue of count1 is %d, Value of count2 is %d", count1, count2); } </code></pre> <p>Initialization means assigning a value to a variable during the declaration of that variable(during intial stage). Assigining values after declaration is just assignment not initialization.</p> <p>For a static variable initialization will be done only once, but the assignment can be done for any number of times.</p> <p>Now in your first program, you are doing <code>a=15;</code>, you are thinking like <code>=</code> operation is not possible in 2nd time and <code>++</code> operation is possible for many times for a static variable.</p> <p>In your program <code>a=15;</code> can be written as below also with <code>++</code> operation.</p> <pre><code>for(j = 0; j = 15; j++) { a++; } </code></pre> <p>So assignment (<code>=</code>) operation is valid on a static variable even in second time also.</p>
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