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POhttpmultipart request for this webservice getdata code in c# with android
 

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    <p>HI i have a webservice IIS with this code:</p> <pre><code> // Implements multipart/form-data POST in C# http://www.ietf.org/rfc/rfc2388.txt // http://www.briangrinstead.com/blog/multipart-form-post-in-c public static class FormUpload { private static readonly Encoding encoding = Encoding.UTF8; public static HttpWebResponse MultipartFormDataPost(string postUrl, string userAgent, Dictionary&lt;string, object&gt; postParameters) { string formDataBoundary = String.Format("----------{0:N}", Guid.NewGuid()); string contentType = "multipart/form-data; boundary=" + formDataBoundary; byte[] formData = GetMultipartFormData(postParameters, formDataBoundary); return PostForm(postUrl, userAgent, contentType, formData); } private static HttpWebResponse PostForm(string postUrl, string userAgent, string contentType, byte[] formData) { HttpWebRequest request = WebRequest.Create(postUrl) as HttpWebRequest; if (request == null) { throw new NullReferenceException("request is not a http request"); } // Set up the request properties. request.Method = "POST"; request.ContentType = contentType; request.UserAgent = userAgent; request.CookieContainer = new CookieContainer(); request.ContentLength = formData.Length; // You could add authentication here as well if needed: // request.PreAuthenticate = true; // request.AuthenticationLevel = System.Net.Security.AuthenticationLevel.MutualAuthRequested; // request.Headers.Add("Authorization", "Basic " + Convert.ToBase64String(System.Text.Encoding.Default.GetBytes("username" + ":" + "password"))); // Send the form data to the request. using (Stream requestStream = request.GetRequestStream()) { requestStream.Write(formData, 0, formData.Length); requestStream.Close(); } return request.GetResponse() as HttpWebResponse; } private static byte[] GetMultipartFormData(Dictionary&lt;string, object&gt; postParameters, string boundary) { Stream formDataStream = new System.IO.MemoryStream(); bool needsCLRF = false; foreach (var param in postParameters) { // Thanks to feedback from commenters, add a CRLF to allow multiple parameters to be added. // Skip it on the first parameter, add it to subsequent parameters. if (needsCLRF) formDataStream.Write(encoding.GetBytes("\r\n"), 0, encoding.GetByteCount("\r\n")); needsCLRF = true; if (param.Value is FileParameter) { FileParameter fileToUpload = (FileParameter)param.Value; // Add just the first part of this param, since we will write the file data directly to the Stream string header = string.Format("--{0}\r\nContent-Disposition: form-data; name=\"{1}\"; filename=\"{2}\";\r\nContent-Type: {3}\r\n\r\n", boundary, param.Key, fileToUpload.FileName ?? param.Key, fileToUpload.ContentType ?? "application/octet-stream"); formDataStream.Write(encoding.GetBytes(header), 0, encoding.GetByteCount(header)); // Write the file data directly to the Stream, rather than serializing it to a string. formDataStream.Write(fileToUpload.File, 0, fileToUpload.File.Length); } else { string postData = string.Format("--{0}\r\nContent-Disposition: form-data; name=\"{1}\"\r\n\r\n{2}", boundary, param.Key, param.Value); formDataStream.Write(encoding.GetBytes(postData), 0, encoding.GetByteCount(postData)); } } // Add the end of the request. Start with a newline string footer = "\r\n--" + boundary + "--\r\n"; formDataStream.Write(encoding.GetBytes(footer), 0, encoding.GetByteCount(footer)); // Dump the Stream into a byte[] formDataStream.Position = 0; byte[] formData = new byte[formDataStream.Length]; formDataStream.Read(formData, 0, formData.Length); formDataStream.Close(); return formData; } public class FileParameter { public byte[] File { get; set; } public string FileName { get; set; } public string ContentType { get; set; } public FileParameter(byte[] file) : this(file, null) { } public FileParameter(byte[] file, string filename) : this(file, filename, null) { } public FileParameter(byte[] file, string filename, string contenttype) { File = file; FileName = filename; ContentType = contenttype; } } } </code></pre> <p>Obtain from here: <a href="https://stackoverflow.com/questions/219827/multipart-forms-from-c-sharp-client">Multipart forms from C# client</a></p> <p>But now, in mi android aplicattion i have this:</p> <pre><code>HttpParams httpParameters = new BasicHttpParams(); int timeoutConnection = 300000; HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection); int timeoutSocket = 300000; HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket); HttpClient httpClient = new DefaultHttpClient(httpParameters); HttpPost postRequest = new HttpPost("http://172.21.1.87:9999/Service1.svc"); ByteArrayBody bab = new ByteArrayBody(ficheroAEnviar, "prueba.jpg"); MultipartEntity reqEntity = new MultipartEntity(); postRequest.addHeader("Content-Type", " multipart/form-data"); reqEntity.addPart("Dictionary", new FileBody(new File(fileUri.toString(), "application/zip"))); reqEntity.addPart("boundary", new StringBody("envio")); postRequest.setEntity(reqEntity); HttpResponse response = httpClient.execute(postRequest); BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "UTF-8")); String sResponse; StringBuilder s = new StringBuilder(); postRequest.getAllHeaders(); while ((sResponse = reader.readLine()) != null) { s = s.append(sResponse); } System.out.println("Response: " + s); } catch (Exception e) { // handle exception here Log.e(e.getClass().getName(), e.getMessage()); } } </code></pre> <p>But it return me Bad request 400 error. Can i use the c# code to upload a multipartentity file with android or a need to make any change in some code?</p> <p>Anyone have a example en c# and android to make this? Is for uppload videos about 10 or 15 MB.</p> <p>Thanks </p>
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