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    <p>Here is a solution that avoids editing your data:</p> <p>Say your plot is facetted by the <code>group</code> part of your dataframe, which has levels <code>control, test1, test2</code>, then create a list named by those values:</p> <pre><code>hospital_names &lt;- list( 'Hospital#1'="Some Hospital", 'Hospital#2'="Another Hospital", 'Hospital#3'="Hospital Number 3", 'Hospital#4'="The Other Hospital" ) </code></pre> <p>Then create a 'labeller' function, and push it into your facet_grid call:</p> <pre><code>hospital_labeller &lt;- function(variable,value){ return(hospital_names[value]) } ggplot(survey,aes(x=age)) + stat_bin(aes(n=nrow(h3),y=..count../n), binwidth=10) + facet_grid(hospital ~ ., labeller=hospital_labeller) ... </code></pre> <p>This uses the levels of the data frame to index the hospital_names list, returning the list values (the correct names).</p> <hr> <p>Please note that this only works if you only have one faceting variable. If you have two facets, then your labeller function needs to return a different name vector for each facet. You can do this with something like :</p> <pre><code>plot_labeller &lt;- function(variable,value){ if (variable=='facet1') { return(facet1_names[value]) } else { return(facet2_names[value]) } } </code></pre> <p>Where <code>facet1_names</code> and <code>facet2_names</code> are pre-defined lists of names indexed by the facet index names ('Hostpital#1', etc.).</p> <hr> <p><strong>Edit:</strong> The above method fails if you pass a variable/value combination that the labeller doesn't know. You can add a fail-safe for unknown variables like this:</p> <pre><code>plot_labeller &lt;- function(variable,value){ if (variable=='facet1') { return(facet1_names[value]) } else if (variable=='facet2') { return(facet2_names[value]) } else { return(as.character(value)) } } </code></pre> <hr> <p>Answer adapted from <a href="https://stackoverflow.com/questions/2893005/how-to-change-strip-text-labels-in-ggplot-with-facet-and-margin-true">how to change strip.text labels in ggplot with facet and margin=TRUE</a></p> <hr> <p><del>edit: <strong>WARNING</strong>: if you're using this method to facet by a <em>character</em> column, you may be getting incorrect labels. See <a href="https://github.com/hadley/ggplot2/issues/1070" rel="noreferrer">this bug report</a>.</del> fixed in recent versions of ggplot2.</p>
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